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3 years ago

the relative molecular mass and formula mass are borth called Mrfor short. what is the difference between them

Chemistry

1 answer:

Ghella [55]3 years ago

4 0

Explanation:

The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance.

In elements which are single atoms, the molar mass is the relative atomic mass is expressed in grams e.g 16g for Oxygen.

If an element is under consideration in molecular state, the molar mass is the molecular mass e.g O₂ is 32g.

In a compound, the molar mass is given as the gram-formula mass or gram-molecular weight. This is determined by the addition of its component atomic masses and then expressed in grams e.g:

NaCl = 23 + 35.5 = 58.5g

Learn more:

Molar mass brainly.com/question/2861244

#learnwithBrainly

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A soft silvery metal has two naturally occurring isotopes: mass 84.9118, accounting for 72.15% and mass 86.9092, accounting for

zloy xaker [14]

Answer: The atomic weight of the metal would be 85.47.

Explanation:

Mass of isotope 1 of metal = 84.9118

% abundance of isotope 1 of metal = 72.15% = $\frac{72.15}{100}$

Mass of isotope 2 of metal= 86.9092

% abundance of isotope 2 of metal = 27.85% = $\frac{27.85}{100}$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(84.9118)\times \frac{72.15}{100})+(86.9092)\times \frac{27.85}{100}]]$

$A=85.47$

Therefore, the atomic weight of the metal would be 85.47.

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slega [8]

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You are the medical examiner at the scene of a murder at a restaurant. There is a

Hoochie [10]

The compound : C₄₀H₄₄N₄O

<h3>Further explanation</h3>

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

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• Determine the mole ratio by dividing the percentage by the atomic mass

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$\tt \dfrac{80.66}{12}\div \dfrac{7.39}{1}\div \dfrac{9.39}{14}\div \dfrac{2.68}{16}\\\\6.722\div 7.39\div 0.671\div 0.1675\rightarrow divide~by~smallest(0.1675)\\\\40\div 44\div 4\div 1$

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jeka57 [31]

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The rabbit prey population will decrease.

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