The sample contains both Fe and oxygen
The mass of the sample is 36 g
28 g are Fe and 8 g are O
So to find the percent composition we can calculate using the following formula
Percent composition of the element = mass of the element / mass of the sample x 100%
Percent composition of Fe = 28 g / 36 g x 100 % = 77.8%
Percent composition of O = 8 g / 36 g x 100 % = 22.2%
Answer:
The value of maximum pressure the balloon could be filled = 6.40 atmosphere.
Explanation:
When helium from the cylinder is filled inside the balloon the heat & work
transfer is zero during the process. so from the first law of thermodynamics
change in internal energy is zero.
⇒
= 0
⇒
= 
⇒
=
------------- (1)
Final temperature is equal to initial temperature.
Equation (1) can be written as
⇒
=
-------------(2)
Initial volume = 44 L
Final volume = 296 L
Initial pressure = 43.1 atmosphere
Final pressure = we have to calculate
Put all the values in Equation (2) we get,
⇒
× 296 = 43.1 × 44
⇒
= 6.40 atmosphere
This is the value of maximum pressure the balloon could be filled.
Explanation:
this is because water cools down heat
There is no hydrogen in ammonium sulfide it is just 1 ammonium and 1 sulfer
Answer:
Kc = 3.90
Explanation:
CO reacts with
to form
and
. balanced reaction is:

No. of moles of CO = 0.800 mol
No. of moles of
= 2.40 mol
Volume = 8.00 L
Concentration = 
Concentration of CO = 
Concentration of
= 

Initial 0.100 0.300 0 0
equi. 0.100 -x 0.300 - 3x x x
It is given that,
at equilibrium
= 0.309/8.00 = 0.0386 M
So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M
At equilibrium
= 0.300 - 0.0386 × 3 = 0.184 M
At equilibrium
= 0.0386 M
![Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2O%5D%5BCH_4%5D%7D%7B%5BCO%5D%5BH_2%5D%5E3%7D)
