One factor of 32 is
2 answers:
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Answer:
We accept the null hypothesis, that is, the the mean amount of garbage per bin is not different from 50.
Step-by-step explanation:
A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50.
This means that the null hypothesis is:
And the alternate hypothesis is:
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
50 tested at the null hypothesis:
This means that
In a random sample of 36 bins, the sample mean amount was 50.67 pounds and the sample standard deviation was 3.9 pounds.
This means that
Value of the test statistic:
p-value:
Since we are testing if the mean is differente from a value and the z-score is positive, the pvalue is 2 multipled by 1 subtracted by the pvalue of z = 1.03.
z = 1.03 has a pvalue of 0.8485
1 - 0.8485 = 0.1515
2*0.1515 = 0.3030
0.3030 > 0.01, which means that we accept the null hypothesis, that is, the the mean amount of garbage per bin is not different from 50.
Using weighted average, it is found that she should score 67% on the computer science test.
- The weighted average is given by <u>each proportion multiplied by it's score</u>.
In this problem, the proportions and scores are given by:
- Proportion of 32% = 0.32 for a score of 300.
- Proportion of x for a score of 200.
- Proportion of 46% = 0.46 for a score of 300 + 200 = 500.
Then
She should score 67% on the computer science test.
A similar problem is given at brainly.com/question/24855677