Answer:

Step-by-step explanation:
![\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%3D%20%5Cfrac%7Bx%5E2%28y-2%29%7D%7B3y%7D%20%5C%5C%5C%5CPut%20%5C%20x%20%3D%203%2C%20%5C%20y%20%3D%20-1%5C%5C%5C%5C%3D%20%5Cfrac%7B%283%29%5E2%28-1-2%29%7D%7B3%28-1%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B9%28-3%29%7D%7B-3%7D%20%5C%5C%5C%5C%3D%209%20%5C%5C%5C%5C%20%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
(For full answer you might have to go to the comments)
Answer: 28x+30
Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
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(x^2+3x+3) 3x^3-2x^2+4x-3
-(3x^3+9x^2+9x)
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-11x^2-5x-3
-(-11x^2-33x-33)
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28x+30
So our remainder will be 28x+30
It is not a question it’s telling you to do it haha! But just divide the (hours of / days) for example 7/2 and that would be your answer!
Answer:
x = 1/5
y = 6
Step-by-step explanation:
System:
{5x + y = 7
{20x + 2 = y
First equation:
5x + y = 7 -> y = -5x + 7
Plug into second equation:
20x + 2 = -5x + 7
Subtract 2 from both sides:
20x = -5x + 5
Add 5x to both sides:
25x = 5
Divde both sides by 25:
x = 5/25 -> 1/5
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Come back to the first equation:
5x + y = 7
Plus in our x:
5(1/5) + y = 7
Multiply:
1 + y = 7
Subtract 1 from both sides:
y = 6
Hope this helps, have a nice day! :D