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Crazy boy [7]
3 years ago
12

Me dicen la respuesta porfa

Mathematics
1 answer:
vovikov84 [41]3 years ago
7 0

Answer:

la respuesta es la tercera abajo

Step-by-step explanation:

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What is the remainder for 1820 divided by 75? REMANIDER
kicyunya [14]
It would be 26 repeating itself
3 0
3 years ago
chad buys peanut in 2-pound bags.He repackages them into bags that hold 5/6 pound of peanuts.How many 2-pound bags of peanuts sh
Nataliya [291]
First, let's find out how many 5/6 pound bags he can fill with on 2 pound bag.

2 divided by 5/6
2 x 6/5
2.4

He can fill 2.4 bags with one 2 bag.
Now we just need to multiply 2.4 by a number that will make it a whole number. You can use the guess and check method starting with 2 to figure your answer out, but 2.4 x 5 = 12 which is a whole number.

This means that Chad needs to buy 5 of the 2 pound bags to fill 12 of the 5/6 pound bags, and he will not have peanuts leftover

6 0
3 years ago
Can someone please help me. This is an equation for either an arithmetic or geometric sequence.
djyliett [7]
A6 = -8
a15= -62

There are (15 - 6) terms in between, therefore 9 terms in between.
-8 to -62 ... there is a difference of 54
54 ÷ 9 = 6
Therefore it gets -6 each term.
a6 = -8, a7= -14, a8 = -20 ......




4 0
3 years ago
Read 2 more answers
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
30,49,30,44,40,35<br>Mean:<br>Mode:<br>Media:<br>Range:​
Otrada [13]

Answer:

mean:38

mode:30

median:37.5

range:19

Step-by-step explanation:

7 0
3 years ago
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