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Nuetrik [128]
2 years ago
15

Can someone please help me. This is an equation for either an arithmetic or geometric sequence.

Mathematics
2 answers:
djyliett [7]2 years ago
4 0
A6 = -8
a15= -62

There are (15 - 6) terms in between, therefore 9 terms in between.
-8 to -62 ... there is a difference of 54
54 ÷ 9 = 6
Therefore it gets -6 each term.
a6 = -8, a7= -14, a8 = -20 ......




Ray Of Light [21]2 years ago
3 0
That's an arithmetic sequence. To find the rule of the sequence, we need to find the first term (a₁) and the difference of the sequence (d)

Make an equation system based on what are given by the question.
an = a₁ + d(n - 1)

a₆ = a₁ + d(6 - 1) = -8
a₆ = a₁ + 5d = -8 (first equation)

a₁₅ = a₁ + d(15 - 1) = -62
a₁₅ = a₁ + 14d = -62 (second equation)

Solve the equation to find the value of a₁ and d
Using elimination method, find the value of d from first equation and second equation
a₁ + 14d = -62
a₁ +  5d =   -8
-------------------- -   (substract)
        9d = -54
          d = -54/9
          d = -6

Using subtitution method, find the value of a₁. Subtitute d with -6 from the first equation.
a₁ + 5d = -8
a₁ + 5(-6) = -8
a₁ - 30 = -8
a₁ = -8 + 30
a₁ = 22

Determine the rule of the sequence
General rule for arithmetic sequence is
an = a + d(n - 1)

Now input the value of a₁ and d to the general rule, then simpllify.
an = a + d(n - 1)
an = 22 + -6(n - 1)
an = 22 -6n + 6
an = 28 - 6n

The rule of the sequence is 28 - 6n
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PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!​
KonstantinChe [14]

Answer:

b.  \displaystyle \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle H(x) = \sqrt[3]{F(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. Rewrite function [Exponential Rule - Root Rewrite]:                                      \displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}
  2. Chain Rule:                                                                                                        \displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]
  3. Basic Power Rule:                                                                                             \displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)
  4. Simplify:                                                                                                             \displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}
  5. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}
  2. Substitute in function values:                                                                          \displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}
  3. Exponents:                                                                                                        \displaystyle H'(5) = \frac{6}{3(4)}
  4. Multiply:                                                                                                             \displaystyle H'(5) = \frac{6}{12}
  5. Simplify:                                                                                                             \displaystyle H'(5) = \frac{1}{2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

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3 years ago
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Digiron [165]

Answer:

F=1

Step-by-step explanation:

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4 0
2 years ago
The cost of a pair of jeans was changed from $47 to $42.13. What was the percent change?
zhenek [66]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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DiKsa [7]
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Vladimir [108]

Step-by-step explanation:

gradient = slope or several other words.

it describes how strongly a line (or tangent to a bent curve) is going up or down or ... if it is changing at all.

it is represented by the ratio

(y coordinate change / x coordinate change)

when going from one point on the line to another.

in our case, when going from A to B we have

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y changes by -11 (from 8 to -3).

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B = (11/6, -3)

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