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3 years ago

15

if there were 24 cookies and then the next day there was 14 left. what percent of cookies were eaten?

2 answers:

cricket20 [7]3 years ago

7 0

If there were 24 cookies and 14 were eaten there was 58% eaten

Dominik [7]3 years ago

3 0

Answer:

Step-by-step explanation:

If there were 24 cookie, and 14 were left

the percentage of cookies eaten is:

we will do:

24/100=14/x

x=14*100/24=58.33%

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Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

In cos(0.3), what unit would 0.3 be? Is it radians? Also if you were to solve it, would the answer be in radians as well? Please

neonofarm [45]

Answer:

22

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Whats the word phrase of 49+m?

Arturiano [62]

The sum of 49 and m.

3 0

3 years ago

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A rectangular prism had a volume of 252 cubic centimeters. The length of the prism is 14 centimeters and the width of the prism

mojhsa [17]

<h2>Answer:</h2>

A prism is a solid object having two identical bases, hence the same cross section along the length. Prism are called after the name of their base. A rectangular prism is a solid whose base is a rectangle. Multiplying the three dimensions of a rectangular prism: length, width and height, gives us the volume of a prism:

$V=L\times W\times H$

FOR THE ORIGINAL PRISM WE HAVE THE FOLLOWING DIMENSIONS:

$L=14cm \\ \\ W=6cm \\ \\ H=3cm$

In fact, the volume is $252cm^3$ because:

$V=14\times 6\times 3 \therefore V=252cm^3$

Now the height of the prism was changed from 3 centimeters to 6 centimeters to create a new rectangular prism, therefore:

FOR THE NEW PRISM WE HAVE THE FOLLOWING DIMENSIONS:

$L=14cm \\ \\ W=6cm \\ \\ H=6cm$

So the new volume is:

$V=14\times 6\times 6 \therefore V=504cm^3$

<h3><em>What do we know about the volume of the new prism?</em></h3>

<em>Well, the volume has increased from </em> $252cm^3 \ to \ 504cm^3$ <em>and since</em> $504=2\times 252$ <em>we can say that the new volume is two times the original volume.</em>

8 0

3 years ago

Graph and label each figure and it’s image under the given translation. Give the coordinates of the image.

lutik1710 [3]

Answer:

See below ~

Step-by-step explanation:

<u>Question 3 : (x, y - 5)</u>

K' = (-3, 2 - 5) = <u>(-3, -3)</u>
L' = (1, 4 - 5) = <u>(1, -1)</u>
M' = (-1, 0 - 5) = <u>(-1, -5)</u>
N' = (-5, -2 - 5) = <u>(-5, -7)</u>

<u></u>

<u>Question 4 : (x + 4, y + 1)</u>

D' = (-4 + 4, 3 + 1) = <u>(0, 4)</u>
E' = (0 + 4, 2 + 1) = <u>(4, 3)</u>
F' = (-2 + 4, -6 + 1) = <u>(2, -5)</u>
G' = (-6 + 4, -5 + 1) = <u>(-2, -4)</u>

5 0

2 years ago