Question

Pls help i will give brainly!!!!!!

Answer 1

Answer:

$\frac{x^{2} }{10} -\frac{y^{2} }{15} = 1$

Step-by-step explanation:

since the foci is (±5,0), the standard form of the hyperbola would be $\frac{x^{2} }{a^{2} } -\frac{y^{2} }{b^{2} } = 1$

directics = ±a^2/c

±2 = ±a^2/5

a^2 = 10

a^2+b^2=c^2

b^2 = c^2-a^2 =5^2-10 = 15