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lara [203]
3 years ago
6

how can you make the gravitational force between two 50kg objects less than the gravitational force between two 5kg objects

Chemistry
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

By increasing the distance between the two 50 kg objects compared with the distance between the 5 kg objects.

Explanation:

The formula for the force between 2 objects is

Fg   = (G m1 m2) / r^2

where Fg is the force,  G = gravitational constant, m1 and m2 are the masses of the objects and r = the distance between the objects.

So as r is increased  Fg is  decreased.

Paraphin [41]3 years ago
3 0

Explanation:

The gravitational force between two 50kg objects could be less than the gravitational force between a 50kg and a 5kg object if the two 50kg objects are much farther apart.

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Answer:

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How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

Temperature =23°c

The formula we would be applying is Ideal gas law

PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

V = Volume = 5.00L

R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

The formula for number of moles =

n = PV/RT

n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K

n = 1.0834112811moles

Step 2

We calculate the mass of Flourine gas

The molar mass of Flourine gas =

F2 = 19 × 2

= 38 g/mol

Mass of Flourine gas = Molar mass of Flourine gas × No of moles

Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

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Ne, Ar, and Kr have which properties in common? Group of answer choices
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