Assuming that the gas acts like an ideal gas, we can
calculate for the final volume using the ideal gas law:
PV = nRT
Where P = pressure, V = volume, n = number of moles, R = gas
constant, and T = temperature
Assuming that P, n, and R are constant throughout the
process, we can define another constant K:
V / T = K where
K = nR / P
Equating the initial and final states:
Vi / Ti = Vf / Tf
Substituting the given values:
11.5 cm^3 / 415 K = Vf / 200 K
Vf = 5.54 cm^3
This problem is easily solvable because radioactivity equations are common and well-established. The pseudo-first reaction is written below:
A = A₀(1/2)^(t/h)
where
A is the final amount
A₀ is the original amount
t is the time
h is the half life
5,000 = A₀(1/2)^(24,000/6,000)
Solving for A₀,
<em>A₀ = 80,000 atoms</em>
Answer:
The new volume of the gas remains the same. That is new volume of gas is 1.33 litres
Explanation:
This is because gases do not have a definite shape. They therefore take the shape of their containing vessels and hence their volumes are determined by the volume of the container.
For the question above even if some of the gas escapes, as long as there is gas present in the container, its volume remains the same, that is occupies the same space in the container
Gas and liquid both take the shape of their container. The difference is gas molecules equally fills the space. Is there any more information?
Explanation:
Magnesium has atomic number 12. It will be distributed in K, L, M shell in the following way:
K shell can accommodate a maximum of 2 electrons.
L shell can accommodate a maximum of 8 electrons and
M shell will accommodate 2 electrons
So the configuration becomes 2, 8,3
