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Maksim231197 [3]
3 years ago
11

Combustion reactions are a notable source of carbon dioxide in the environment. Using the following balanced equation, how many

grams of carbon dioxide are formed when 100.00 g of propane is burned? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. Equation: C3H8 + 5O2 ->>>>>>> 3CO2 + 4H2O
Chemistry
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

Explanation:

Number of moles of propane:

=Mass in grams ÷ Relative molecular Mass

= 100/((12*3) + (1*8))

= 100 ÷ 44

= 2.2727

Mole ratio propane:carbon (IV) oxide = 1:3(from the equation)

Number of moles of CO2 = 3*2.2727 = 6.8181

Mass in grams = Relative molecular Mass * Number of moles

= 44 * 6.8181

= 299.9964 grams

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A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of 0.157g of the compound produced 0.213g of CO2 and
vladimir2022 [97]

Answer:

C_{7} H_{5}N_{3}O_{6}

Explanation:

First reaction gives you the number of moles or the mass from Carbon and hydrogen

for carbon:

0,213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} =0.005molC

0.213gCO_{2} .\frac{1molCO_{2}}{44gCO_{2}} .\frac{1molC}{1molCO_{2}} .\frac{12gC}{1molC} = 0.058gC\\

Analogously for hydrogen:

0.0310gH_{2}O have 0.0034gH or 0.0034mol of H

In the second reaction you can obtain the amount of nitrogen as a percentage and find the mass of N in the first sample.

0.023gNH_{3} .\frac{1molNH_{3}}{17gNH_{3}} .\frac{1molN}{1molNH_{3}} .\frac{14gN}{1molN} \frac{100}{0.103gsample} =18.4%N

now

\frac{18.4gN}{100gsample} .0.157gsample=0.0289gN in the first reaction

this is equivalet to 0.002mol of N

with this information you can find the mass of oxygen by matter conservation.

gO=total mass-(gN+gC+gH)=0.157-(0.0289+0.058+0.0034)=0.0666gO

this is equivalent to 0.004molO

finally you divide all moles obtained between the smaller number of mole (this is mol of H)

C\frac{0.0048}{0.0034} H\frac{0.0034}{0.0034} N\frac{0.002}{0.0034} O\frac{0.004}{0.0034} =C_{1.4} HN_{0.6} O_{1.2}

and you can multiply by  5   to obtain: C_{7} H_{5}N_{3}O_{6}

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Explanation:

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Calculate no. Of moles in 329g of H2so4
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Mol= mass (grams) /Mr
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Monique hears on the weather report that cold, dry air from Canada is going to hit warm, moist air from the Gulf of Mexico. She
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