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charle [14.2K]
2 years ago
8

Quiénes son losexpertos parahablarnos sobrealimentación?:​

Chemistry
1 answer:
Fantom [35]2 years ago
3 0

Answer:

es nutricionista el experto en esa area

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Which element is present in all organic compounds?
Mkey [24]
The anser is 1, carbon
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2 years ago
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What is an element in the alkali metal group
Tema [17]

Answer:

Group of highly-reactive chemical elements. The alkali metals are a group (column) in the periodic table consisting of the chemical elements lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr).

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The men's world record for swimming 1500 m in a long course pool is 14 min 34.56 s. At this rate how many seconds would it take
vlabodo [156]
Distance = 1500m, time = 14min 34.56s = 14*60 + 34.56 = 874.56s

Speed = Distance / time = 1500/874.56 = 1.715 m/s

In order to swim 0.7 miles, 1 mile = 1609.344 m

Time = Distance / speed = 1609.344 m / 1.715 m/s = 938.393 seconds

938/60 = 15 minutes, 38 seconds.

= 15 minutes 38.393 seconds.
6 0
3 years ago
Which acid has the largest ka: hclo3(aq), hbro3(aq) or hio3(aq)?
ryzh [129]
Greater the Ka value greater is the acid strength. Among these three acids HClO3 is the strongest acid, with greatest Ka and lowest pKa value (-1), Then comes HBrO3, its the second most strongest acid among the three, its Pka value is 0.7, higher than HClO3 but smaller than HIO3 (i.e. 0.77) which the weakest acid among the three.

3 0
3 years ago
05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises
OLga [1]

Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

Mass of gold =.?

Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

Note: 1 mL is equivalent to 1 cm³

Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

Therefore, the mass of the gold pebble is 142.82 g

6 0
3 years ago
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