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horrorfan [7]
3 years ago
15

Number of balance electrons of a non ionized oxygen atom​

Chemistry
1 answer:
Iteru [2.4K]3 years ago
7 0
Do you mean valence electrons? I think it’s 7 I’m not sure though it’s been a while
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puteri [66]
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3 years ago
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inna [77]

Answer: d. smaller.

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N=\frac{1}{2}[V+N+A-C]

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where, V = number of valence electrons present in central atom i.e. oxygen = 6

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The number of electrons is 4 that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.  The bond angle for tetrahedral geometry is 109.5^0

But as there are two atoms around the central oxygen, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent and the bond angle will be smaller than expected and is 104.5^0

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These are correct. Ironic they are already in the correct order.

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