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3 years ago

Is it possible for number of moles to be less than one?

Chemistry

1 answer:

Advocard [28]3 years ago

8 0

Answer:

yes is very possible to be

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3 years ago

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A ballon begins at sea level at 1 atm. It rises in the atmosphere to where the pressure is lower, to where the pressure is .75 a

maxonik [38]

Answer:

Original volume=3L

Explanation:

Assuming the gas in the ballon is ideal and the temperature does not vary with height we have the gas law as

PV=nRT

Here RHS is constant in both the conditions which means

PV=constant

Given P1=1 atm V1=V P2=0.75atm V2=4L

P1V1=P2V2

$1*V=0.75*4$

V=3L

The initial volume of the gas is 3L

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3 years ago

How many grams of Sodium metal are required to completely react with 100 g of Magnesium chloride hexahydrate in a single replace

slava [35]

Answer:

MgCl2 - 6H2O

203.3 mol

MgCl2 + 2Na = 2NaCl + Mg

22.6g

Explanation:

1. Write the formula of hydrate and find molar mass.

2. Write a balanced single replacement (don't include H2O)

3. Do the given/wanted calculation (include H2O in molar mass of given)

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3 years ago

HELP IT IS DUE TOMORROW!!fill out the last column of the table . Do they use ionic or covalent bonding

morpeh [17]

C = covalent

I = Ionic

(I'm lazy to an extent)

An ionic bond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals.

H2 = C

Cl2 = C

O2 = C

HCl = C

LiF = I

NaCl = I

NaF = I

MgF = I

NH3 = C

CH4 = C

CO2 = C

NaP = I

N2 = C

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3 years ago

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When a 2.75g sample of liquid octane (C8H18) is burned in a bomb calorimeter, the temperature of the calorimeter rises from 22.0

OLEGan [10]

Answer:

THE HEAT OF COMBUSTION IS 4995.69 kJ/mol OF OCTANE.

Explanation:

Heat capacity = 6.18 kJ/C

Temperature change = 41.5 C - 22.0 C = 19.5 C

Heat required to raise the temperature by 19.5 °C is:

Heat = heat capacity * temperature change

Heat = 6.18 kJ/ C * 19.5 C

heat = 120.51 kJ of heat

120.51 kJ of heat is required to raise the temperature of 2.75 g sample of a liquid octane.

Molar mass of octane = ( 12* 8 + 1 * 18) = 114 g/mol

So therefore, the heat of the reaction per mole of octane will be:

120.51 kJ of heat is required for 2.75 g of octane

x J of heat will be required for 114 g of octane

x J = 120.51kJ * 114 / 2.75

x = 4995.69 kJ of heat per mole.

In conclusion, the heat of the combustion reaction in kJ / mole of octane is 4995.69 kJ/mol

4 0

3 years ago

Is it possible for number of moles to be less than one?​

Is it possible for number of moles to be less than one?