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3 years ago

In order for a solute to dissolve in a solvent, what must be true?

Chemistry

1 answer:

Alex Ar [27]3 years ago

6 0

The solute has to be hydrophilic, (water loving).

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Predict how maritime air masses would change if the ocean froze

MrRissso [65]

Air moves from

high(pressure)the regions at the

poles(d0)

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2 years ago

Locations Cost of land Cost of equipment Cost of mining and reclamation Time taken to mine the area 1 $100,000 $10,000 $5,000 pe

mario62 [17]

Answer:

Location 2 will cost the least to the company to mine.

Explanation:

a) Data and Calculations:

Locations Cost of land Cost of Cost of mining Time taken to

equipment and reclamation mine the area

1 $100,000 $10,000 $5,000 per day 30 days

2 $35,000 $6,000 $4,500 per day 45 days

3 $30,000 $7,500 $3,500 per day 120 days

4 $40,500 $8,000 $7,000 per day 65 days

Locations Cost of land Cost of Cost of mining Total

equipment and reclamation Costs

1 $100,000 $10,000 $150,000 ($5,000 * 30) $260,000

2 $35,000 $6,000 $202,500 ($4,500 * 45) $243,500

3 $30,000 $7,500 $420,000 ($3,500 * 120) $457,500

4 $40,500 $8,000 $445,000 ($7,000 * 65) $503,500

7 0

2 years ago

Which of the following uses a nonrenewable energy resource to generate energy? A. nuclear power plant B. wind farm C. fireplace

asambeis [7]

The answer is bimass power plant.

4 0

2 years ago

He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o

Xelga [282]

Answer : The activation energy of the reaction is, $17.285\times 10^4kJ/mole$

Solution :

The relation between the rate constant the activation energy is,

$\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = initial rate constant = $4.55\times 10^{-5}L/mole\text{ s}$

$K_2$ = final rate constant = $8.75\times 10^{-3}L/mole\text{ s}$

$T_1$ = initial temperature = $195^oC=273+195=468K$

$T_2$ = final temperature = $258^oC=273+258=531K$

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

$\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]$

$Ea=17.285\times 10^4kJ/mole$

Therefore, the activation energy of the reaction is, $17.285\times 10^4kJ/mole$

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3 years ago

Read 2 more answers

Explain why it is important for cells to exchange materials.

Alla [95]

Answer:

they need the exchange so they can grow, obtain energy, and get rid of waste. It also helps to mantian a balance of amterials in the cell.

Explanation:

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3 years ago