In order for a solute to dissolve in a solvent, what must be true?

umka2103 [35]

The answer is c for more heat energy

6 0

3 years ago

Suppose 0.410 kg of hexane are burned in air at a pressure of exactly 1 atm and a temperature of 13.0 °C. Calculate the volume o

3241004551 [841]

Answer:

The answer is 671 litres of carbon dioxide is produced from 0.410 kg of hexane

Explanation:

We first write a balanced reaction for the complete combustion of hexane thus

The stoichiometry of the cumbustion of hexane in air is

2C6H14(g)+18O2(g)→12CO2(g)+14H2O(l) or

C6H14(g)+9O2(g)→6CO2(g)+7H2O(l)

From the above reaction it is observed that one mole of hexane burns completely in the presence of oxygen to produce 6 moles of carbon dioxide

Therefore we calculate the nuber of moles of hexane present in the sample thus

Mass hexane of sample = 0.41 kg

Molar nass of hexane = 86.18 g/mol

number of moles of hexane = (mass of hexane)/(molar mass of hexane) = (0.41×1000)/86.16 = 410/86.16 = 4.76 moles

As we have seen from the chemical reaction, 1 mole of H6H14 produces 6 moles of CO2 hence 4.76 moles of Hexane produces

4.76×6 moles of CO2 which is 28.55 moles of CO2

From the question we have the temperature and the pressure of the production of CO2 as

Temperature of reaction = 13° C converting to kelving gives= 13+273.15 = 286.15 K

and pressure = 1 atmosphere or 101325 Pa

13.0∘C=13.0∘C+273.15=286.15 K

The volume of the produced CO2 can be calculated using the combined ideal gas equation given by

P×V=n×R×T where

Here

P = Gas pressure (of CO2 )

V = Volume (of the CO2)

n = number of moles of gas (CO2) present

R = universal gas constant, equal to 0.0821 atm× L/(mol× K )

T = absolute temperature in Kelvin

Thus we have

1×V = 28.55×0.0821×286.15 or V = 670.76L

Rounding up the answer to 3 significant digits we have

670.76L ≅ 671L

671 litres of carbon dioxide is produced from 0.410 kg of hexane

8 0

4 years ago

The mass of the sedimentary rock is equal to the mass of what

Finger [1]

It would have 018 mass balance calculation and the total of the sedimentary rock mass would like 0.76

8 0

3 years ago

You have separate solutions of HCl and H2SO4 with the same concentrations in terms of molarity. You wish to neutralize a solutio

sergejj [24]

Answer: Option (A) is the correct answer.

Explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to yield salt and water.

The given reaction will be as follows.

$HCl + NaOH \rightarrow NaCl + H_{2}O$

$H_{2}SO_{4} + 2NaOH \rightarrow Na_{2}SO_{4} + 2H_{2}O$

Now, if molarity of NaOH = $M_{1}$ and volume of NaOH = $V_{1}$

Therefore, Molarity of HCl = molarity of $H_{2}SO_{4}$ = $M_{2}$

Volume of HCl required = $\text{molarity of NaOH} \times \frac{\text{volume of NaOH}}{\text{molarity of HCl}}$

= $\frac{M_{1}V_{1}}{M_{2}}$

So, vVolume of $H_{2}SO_{4}$ required = 0.5 x molarity of NaOH x \frac{\text{volume of NaOH}}{\text{molarity of H_{2}SO_{4}}}[/tex]

= $0.5 \times \frac{M_{1}V_{1}}{M_{2}}$

Hence, volume of HCl = 2 x volume of $H_{2}SO_{4}$ .

Thus, we can conclude that HCl solution would be required more volume (in mL) to neutralize the base.

7 0

3 years ago

How many milliliters of boiling water are required to dissolve 25 g of phthalic acid? If the solution were cooled to 14°C, how m

wlad13 [49]

Answer: density = m/volume

25g / 1.59 g /cm3

= 15.72 $cm^{-3}$

Explanation: first you need tp look for the density of the acid

6 0

4 years ago