Answer:
By increasing the pressure, the molar concentration of N2O4 will increase
Explanation:
We have the equation 2NO2 ⇔ N2O4
This equation is reversible and exotherm. By <u>decreasing the temperature</u>, the reaction will produce more energy, so the reaction will move to the right. But a lower temperature also lowers the rate of the process, so, the temperature is set at a compromise value that allows N2O4 to be made at a reasonable rate with an equilibrium concentration that is not too unfavorable
So <u>increasing the temperature</u> will shift the equilibrium to the left. The equilibrium shifts in the direction that consumes energy.
If we d<u>ecrease the concentration of NO2</u>, the equilibrium will shift to the left, resulting in forming more reactants.
To increase the molar concentration of the product N2O4, we have to <u>increase the pressure</u> of the system.
NO2 takes up more space than N2O4, so increasing the pressure would allow the reactant to collide more form more product.
By increasing the pressure, the molar concentration of N2O4 will increase
Crossing your arms across the chest and pulling the knees up to your chest is how the HELP position is achieved.
<h3>What is HELP position?</h3>
This is referred to as heat escape lessening position and reduces heat loss in individuals when in cold water.
This position helps to protect groin, head/neck, and rib cage/armpits areas of the body.
Read more about Heat loss here brainly.com/question/6850851
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Answer:
Since all the acid molecules have split into ions, there will be more H+ ions in a strong acid than a weak acid, hence it's pH is lower! E.g. Hydrochloric acid HCl, nitric acid HNO3. If one mole of an acid is neutralised by 2 moles of NaOH, then the acid is dibasic!
Explanation:
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Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.
Explanation:
Given: Volume of solute = 120 mL
Volume of solvent = 350 mL
Now, total volume of the solution is as follows.
Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.
Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.
Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.
