The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.
1 answer:
Answer:
6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.
Explanation:
The balanced reaction is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Fe₂O₃: 1 mole
- CO: 3 moles
- Fe: 2 moles
- CO₂: 3 moles
The molar mass of each compound is:
- Fe₂O₃: 159.7 g/mole
- CO: 28 g/mol
- Fe: 55.85 g/mole
- CO₂: 44 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- Fe₂O₃: 1 mole* 159.7 g/mole= 159.7 grams
- CO: 3 moles* 28 g/mol= 84 grams
- Fe: 2 moles* 55.85 g/mole= 111.7 grams
- CO₂: 3 moles* 44 g/mole= 132 grams
Then you can apply the following rule of three: if by stoichiometry 111.7 grams of Fe are produced from 159.7 grams of Fe₂O₃, 4.65 grams of Fe are produced from how much mass of Fe₂O₃?
mass of Fe₂O₃= 6.65 grams
<u><em>6.65 grams of Fe₂O₃ are required to produce 4.65g Fe.</em></u>
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Al
Explanation:
The limiting reactant will be Al:
4Al + 3O₂ → 2Al₂O₃
The limiting reactant is the reactant in short supply in a chemical reaction.
Given parameters:
Mass of Al = 30g Molar mass = 27g/mol
Number of moles = =
Number of moles of Al = 1.111 mole
Mass of O₂ = 30g, molar mass = 32g/mol
Number of moles = = 0.94mol
In the reaction:
4 moles of Al reacted with 3 moles of O₂
1.11moles of Al will require = 0.83mole to react
But we have been given 0.94mole of O₂. This is more than required.
Therefore O₂ is in excess and Al is the limiting reactant.
Learn more:
Limiting reagents brainly.com/question/6078553
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