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pantera1 [17]
3 years ago
8

What is the correct formula for Heptarsenic Tetrabromide

Chemistry
1 answer:
harina [27]3 years ago
3 0
Hepta is seven and tetra is four, so option c is your answer
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Oxygen gas can be prepared by heating potassium chlorate according to the following equation: 2KClO3(s)2KCl(s) + 3O2(g) The prod
Ipatiy [6.2K]

Answer:

The number of moles of KClO₃ reacted was 0,15 mol

Explanation:

For the reaction:

2KClO₃(s) → 2KCl(s) + 2O₂(g)

The only gas product is O₂.

Total pressure is the sum of vapor pressure of water with O₂ gas formed. Thus, pressure of O₂ is:

749mmHg - 23,8mmHg = 725,2mmHg

Using gas law:

PV/RT = n

Where:

P is pressure (725,2mmHg ≡ <em>0,9542atm</em>)

V is volume (<em>5,76L</em>)

R is gas constant (<em>0,082 atmL/molK</em>)

And T is temperature (25°C ≡ <em>298,15K</em>)

Replacing, number of moles of O₂ are <em>0,2248 moles</em>

As 2 moles of KClO₃ react with 3 moles of O₂ the moles of KClO₃ that reacted was:

0,2248 mol O₂×\frac{2 mol KClO_{3}}{3 mol O_{2}} = <em>0,15 mol of KClO₃</em>

I hope it helps!

8 0
3 years ago
is the process through which offspring are produced. A. Heredity B. Reproduction C. Conservation D. Vaccination
Dominik [7]
It is called Reproduction 
6 0
3 years ago
Read 2 more answers
A compound is formed when 9.03 g
NikAS [45]

The percent composition  of this compound :

Mg = 72.182%

N = 27.818%

<h3>Further explanation</h3>

Given

9.03 g  Mg

3.48 g  N

Required

The percent composition

Solution

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

Total mass of the compound :

= 9.03 g + 3.48 g

= 12.51 g

The percent composition :

Mg : 9.03/ 12.51 g x 100% = 72.182%

N : 3.48 / 12.51 g x 100% = 27.818%

3 0
3 years ago
Why would methane attain a tetrahedral structure?​
lys-0071 [83]

<h2>HOPE THIS HELPS YOU ....</h2><h3>PLEASE MARK ME AS BRAINILIST...</h3>

3 0
3 years ago
Read 2 more answers
Can someone show their work on how to do this: Calculate the number of moles of Al2O3 present in 23.87g. (Molar mass of Al2O3= 1
vodomira [7]

Answer:

0.234 moles

Explanation:

moles of Al2O3 = mass / molar mass

moles of Al2O3 = 23.87g / 102.0g/mol

moles of Al2O3 = 0.234 moles (to three significant figures)

6 0
3 years ago
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