From the given observations,
You can see that as the concentration is doubled, half-life is halved.
That is,half-life is inversely proportional to concentration
As t( half-life) ~ 1/a^(n-1)
For this case n = 2,second order reaction.
R = k X a^n
Using the above formula you will get the rate and rate constant.
Answer:
m Br = 439.472 g
Explanation:
mass Br = ?
∴ mol Br = 5.50 mol
∴ molar mass Br 79.904 g/mol
mass = (mol)*(g/mol)
⇒ m Br = (5.50 mol)*(79.904 g/mol)
⇒ m Br = 439.472 g
Answer:
The number of moles of nitrogen in the tank are 1,98.
Explanation:
We apply the ideal gas law, convert the temperature unit in Celsius to degrees Kelvin, solve for n (number of moles). The gas constant R is used with a value of 0.082 l atm / K mol:
0°C= 273 K ---> 19, 71°C= 273 + 19,71= 292, 71K
PV= nRT ---> n=PV/RT
n= 4,97 atm x 9,583 L/ 0.082 l atm / K mol x 292, 71K=<em> 1, 98 mol</em>
