Step 3: Measure the speed of the Toy Car on the Lower Track

A scientist discovers a deep bowl-like divot under the ocean off the coast of eastern Mexico that is many kilometers across. The

arsen [322]

Answer:

its B

Explanation:

8 0

3 years ago

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Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur

Alenkinab [10]

Answer:

$\large \boxed{\text{-10.0 kJ}}$

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

$w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}$

The negative sign indicates that the work was done against the surroundings.

4 0

3 years ago

Using the combined gas law, if the volume of a gas at 155kPa changes from 22L to 10L. What is the new pressure if the temperatur

Deffense [45]

Answer:

The answer to your question is P2 = 342 kPa

Explanation:

Data

Pressure 1 = P1 = 155 kPa

Volume 1 = V1 = 22 l

Pressure 2 = P2 = ?

Volume 2 = V2 = 10 l

Temperature = constant

Process

1.- Write the equation of the combined gas law

P1V1/T1 = P2V2/ T2

Cancel T1 and T2 because they measure the same

P1V1 = P2V2

-Solve for P2

P2 = P1V1/V2

2.- Substitution

P2 = (155 x 22) / 10

3.- Simplification

P2 = 3410 / 10

4.- Result

P2 = 342 kPa

5 0

3 years ago

If the molecular weight of a semiconductor is 27.9 grams/mole and the diamond lattice constant is 0.503 nm, what is the density

adelina 88 [10]

Explanation:

The given data is as follows.

Mass = 27.9 g/mol

As we know that according to Avogadro's number there are $6.023 \times 10^{26}$ atom present in 1 mole. Therefore, weight of 1 atom will be as follows.