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inysia [295]
3 years ago
13

Is the picture clear...i reallly need answers

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0
I do not see a picture sadly.
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If 4sintheta = -3, solve for theta given 0°>_theta>_360°
Soloha48 [4]

Answer:

311.41 degrees

Step-by-step explanation:

If 4 sin Ф = -3 and Ф is between 0 and 360 degrees, then we conclude that Ф must be either in Quadrant III or Quadrant IV (because the sine is negative).

Let's assume we're in Quadrant IV.  Then sin Ф = opp / hyp = -3/4; that is, the opp side is negative and has length 3, and the hypo is positive 4.

According to the Pythagorean Theorem,  (-3)^2 + x^2 = 4^2, or,

x^2 = 16 - 9 = 7.

Then x is either √7 or -√7.

To find the angle Ф, use the inverse sine function:

Ф = arcsin (-3/4).  Using a calculator we get the angle -40.59 degrees, which corresponds to (360 degrees - 40.59 degrees), or 311.41 degrees.  We can check this by finding the sine of 311.41 degrees; the result is -0.75, which matches "If 4sintheta = -3."  

6 0
2 years ago
Find the ratio of the area inside the square but outside the circle to the area of the square in the picture
Eduardwww [97]

Answer:

0.2146

Step-by-step explanation:

From the picture:

The radius of the circle = r. This means that the area of the circle = πr²

Also For the square, the length of the square = 2r, Therefore the area of the square = Length × length = 2r × 2r = 4r²

The area inside the square but outside the circle = Area of square - Area of circle = 4r² - πr² = r²(4 - π) = 0.8584r²

The ratio of the area inside the square but outside the circle to the area of the square =  r²(4 - π) / 4r² = (4 - π) / 4 = 1 - π/4 = 0.2146

5 0
3 years ago
If all of the diagonals are drawn from a vertex of a quadrilateral, how many triangles are formed?
sergij07 [2.7K]

Answer:

4

Step-by-step explanation:

From the chioces give it would be 4

But it is actually 8

8 0
2 years ago
Please help I need for graph
Gala2k [10]
For a you will see a bar graph and the dependent o think would be bird species
3 0
2 years ago
For nitrogen to be a liquid, its temperature must be within 12.78 °F of –333.22 °F. Which equation can be used to find the maxim
ziro4ka [17]
To determine the maximum and minimum temperatures at which nitrogen remains a liquid, use the equation |x - (-333.32)| = 12.78, where x is equal to the maximum and minimum temperatures. Using this equation, the maximum temperature is -320.54 degrees Fahrenheit while the minimum is -346.10 degrees Fahrenheit.
3 0
3 years ago
Read 2 more answers
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