Answer:
Part 1) 
Par 2) 
Part 3) 
Step-by-step explanation:
step 1
Find the 
we have

Remember that

therefore

step 2
Find the 
we know that

we have

substitute




square root both sides

we have that
---> given problem
so

step 3
Find the 
we know that

we have


substitute

Simplify

Answer:
C
Step-by-step explanation:
Normal distribution has a unique characteristic of having equal mean and median values. If mean was higher than median, then the distribution would be positively skewed. Mean lower than median would appear in distributions negatively skewed. Each data set has a median value.
Answer:
576 Units
Step-by-step explanation:
The way your teacher wants you to do it:
1. We know that multiplying a length by four gives us the perimeter of a square.
1a. Thus, we multiply the given length by four. 4(10x+4)=40x+16
1b. We know the perimeter is 96. So: 40x+16=96
2. Solving for x, we get x=2
3. Plugging our solved x into the given length (10x+4), we see that the length of a side of the square is 10*2+4=24.
4. We know that the area of a square can be found by squaring the side of a square.
4a. 24*24=576.
5. The area is 576 units.
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Easier Solution:
1. We know that the perimeter is length*4.
2. We set L to length.
2a. 4L=96
2b. L=24
3. We know that the length square is area.
4. 24*24=576.
415
8*50 + 15
Mark brainliest please
If you were to have (3,2) and find the reflection of the y axis, it would turn y into a negative, making it (3,-2).