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2 years ago

What is the smallest positive integer that has 12 factors

Mathematics

1 answer:

Umnica [9.8K]2 years ago

5 0

Answer:

1,2,3,4,5,6,10,12,15,20,30,60

Step-by-step explanation:

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Which value is a solution of the equation 85= 120-w?

Ronch [10]

$85=120-w\\85-120=120-w-120\\-35=-w\\\frac{-35}{-1}=\frac{-w}{-1}\\35=w$

w = 35

8 0

2 years ago

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If a household appliance has a wattage of 6,995 and is in use for 3 hours, how much CO2 was produced? Round to 1 decimal.

Kruka [31]

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2 years ago

From a shipment of 400 light-bulbs, a sample of 80 was selected at random and tested. If 32 light-bulbs in the sample were found

denis-greek [22]

80 x 5 = 400
32 x 5 = 160
so you have about 160 <span>defective bulbs</span>

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3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

3 years ago

Factor x^4+xy^3+x^3+y^3 completely showing work.

babymother [125]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$x^4+xy^3+x^3+y^3\\\\=x^3*x+x*y^3+x^3+y^3\\\\=x(x^3+y^3)+x^3+y^3\\\\\boxed{=(x+1)(x^3+y^3)}\\$

Thank you

4 0

2 years ago