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fiasKO [112]
3 years ago
15

$90.60/12 2/5 = $22.60 /c

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0
The awnser is c=7.48
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What is 3 root 17 in a decimal
finlep [7]

Answer:

\sqrt[3]{17}= 2.57128=257128×10^{-5}

Step-by-step explanation:

We need to find: \sqrt[3]{17} in decimals. To do this, we are going to need the help of a calculator. After plugging the values, we get that:

\sqrt[3]{17}= 2.57128 = 257128×10^{-5}

In this case, I just considered 5 significant figures!

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4 years ago
What would the example problem of the equation 1/4x=2 Be?
11Alexandr11 [23.1K]

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This would be an algebraic problem if that's what you're asking.

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3 years ago
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iragen [17]

Answer:

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Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
A data set includes 106 body temperatures of healthy adult humans having a mean of 98.7degreesF and a standard deviation of 0.66
blondinia [14]

Answer:

The 99% confidence intervals are

(98.4346 , 98.7654)

C) This suggests that the mean body temperature could very possibly be 98.6degrees°F.

<u>Step-by-step explanation:</u>

Given data a data set includes 106 body temperatures of healthy adult humans having a mean of 98.7degreesF and a standard deviation of 0.66degreesF

sample size n = 106

Mean of the population   ' μ' = 98.7degreesF

standard deviation of population 'σ' = 0.66degreesF

Mean of the sample x⁻ = 98.6degreesF

Level of significance ∝ = 0.99 0r 0.01

<u>Confidence limits :-</u>

The values (x^{-} - 2.58\frac{S.D}{\sqrt{n} } ,x^{-} +2.58\frac{S.D}{\sqrt{n} } ) are called 99% of confidence limits

For the mean of the Population corresponding to the given sample.

(98.6 - 2.58\frac{0.66}{\sqrt{106} } ,98.6 +2.58\frac{0.66}{\sqrt{106} } )

on calculation, we get

(98.6 - 0.1654,98.6 + 0.1654)

The 99% confidence intervals are

(98.4346 , 98.7654)

C)<u> This suggests that the mean body temperature could very possibly be 98.6degrees°F</u>.

3 0
3 years ago
Adam currently runs about 20 miles per week, and he wants to increase his weekly mileage by 30%. Howmany miles will Adam run per
andrew-mc [135]
Adam will have to run 26 miles per week. 30% of 20 is 6. (6+20=26)
6 0
3 years ago
Read 2 more answers
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