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fiasKO [112]
3 years ago
15

$90.60/12 2/5 = $22.60 /c

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0
The awnser is c=7.48
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A rectangular poster is to contain 882 square inches of print. The margins at the top and bottom of the poster are to be 2 inche
Zinaida [17]

Answer:

L  =  23 in

h  = 46  in

Step-by-step explanation:

Let call  " x "  and  " y "  dimensions of the print area of the poster then:

882 = x*y  and   y = 882/x

We also know that dimensions of the poster is:

L  =  x + 2   in  and     h  =  y + 4 in

Therefore area of the poster is:

A(p)  = ( x + 2 ) * ( y + 4 )  And area as function of x is:

A(x)  =   ( x + 2 ) * ( 882/x + 4 )

A(x)  =  882 + 4*x + 1764 /x  + 8

Taking derivatives on both sides of the equation we have:

A´(x)  =  4  - 1764/x²

A´(x)  = 0      ⇒      4  - 1764/x² = 0      ⇒ 4*x² - 1764  =  0

x²  =  1764 / 4

x²  = 441

x  = 21 in      and    y  =  882/x         y  = 42

The second derivative  A´´(x)  is > 0  ( the second term changes its sign to +) there is a minimum for the function at the point      x = 21

As x   and  y are dimensions of the printing area of the poster, dimensions of the poster  are

L  = x  +  2   =   21  + 2  =  23 in   and

h = y  +  4   =   42  + 4  =  46  in

4 0
3 years ago
A rotating sprinkler that sprays water at a radius of 11 feet is used to water a lawn. Determine the area of the lawn that is be
Anestetic [448]

Answer:

69.1²feet

Step-by-step explanation:

area = pi x r²

11x2= 22

22x 3.14 = 69.08

69.1

4 0
2 years ago
What would be the answer to writing the equations included in the same set of related facts as 6×8=48
larisa [96]
Included in the same facts
7 0
2 years ago
How can you use polygons to approximate the circumference and area of a circle?
o-na [289]
By dividing the area of the polygon with the circles area.
4 0
3 years ago
Flights arriving to DTW might be national or international. Assume that one out of every five national flights is followed by an
Dvinal [7]

Answer:

1/15

Step-by-step explanation:

Given

1 out of every 5 national flight is followed by an international flight.

p = 1/5

q = 1 - p

q = 1 - 1/5

q = 4/5

π0 = 0.25

We want to determine

p:the fraction of international flights that are followed by a national flight.

Let X = 0

If the nth flight is national

Let X = 1

if the flight is international

This gives rise to a two state Markov chain with transition probability as follows

P = (4/5. 1/5. p. 1-p)

The long run proportion are the below solution gotten from the Markov chain above

π0 = 4/5π0 + pπ1 ----- 1

π1 = 1/5π0 + (1 - p)π1---- 2

π0 + π1 = 1 -----------. 3

Solving the above equations,

We have

Substitute 0.25 for π0 in (3)

0.25 + π1 = 1

π1 = 1 - 0.25

π1 = 0.75

Solving 1 and 3

Substitute 0.75 for π1 and 0.25 for π0 in (1)

0.25 = 4/5 * 0.25 + 0.75p

0.25 = 0.2 + 0.75p

0.75p = 0.25 - 0.2

0.75p = 0.05

p = 0.05/0.75

P = 1/15 or 0.0667(6.67%)

So, one out of every 15 international flights is followed by a national flight (or 6.66 percent)

3 0
3 years ago
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