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Lemur [1.5K]
3 years ago
6

Solve: x/15 - 12 = 8

Mathematics
2 answers:
erica [24]3 years ago
7 0

Answer:  x = 300

Step-by-step explanation:

GREYUIT [131]3 years ago
4 0
X/15 - 12 = 8

Add 12 to both sides of the equation.

x/15 - 12 + 12 = 8 + 12

Simplify the equation

x/15 = 20

Now we are gonna multiply both sides by 15.

15x/15 = 20 * 15

Simplify the equation

x = 300

Therefore x is equal to 300
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Answer:

0.9936 = 99.36% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk, there are only two possible outcomes. Either it works, or it does not. The probability of a disk working is independent of any other disk, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

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Assume that there is a 8​% rate of disk drive failure in a year.

So 100 - 8 = 92% probability of working, which means that p = 0.92

Two disks are used:

This means that n = 2

What is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.92)^{0}.(0.08)^{2} = 0.0064

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0064 = 0.9936

0.9936 = 99.36% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

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