If his best time is x, and the best time is smaller, then (1+1/3)*x=his second best time. If x+4=his second best time (since his second best time is 4 seconds slower), then (1+1/3)*x=x+4. Multiplying it out, we get (3/3+1/3)*x=x+4
=4x/3=x+4. Subtracting x from both sides, we get 4x/3-3x/3=x/3=4. Multiplying both sides by 3, we get x=12=his best time
Part a: 1,3,5,7
part b: i’m not sure
picture attached, you do not have.
Answer:
a ≤ 15
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
3(a - 4) ≤ 33
<u>Step 2: Solve for </u><em><u>a</u></em>
- Divide 3 on both sides: a - 4 ≤ 11
- Add 4 on both sides: a ≤ 15
Here we see that any value <em>a </em>less than or equal to 15 would work as a solution to the inequality.