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makvit [3.9K]
2 years ago
7

A number between 0 and 1, expressed as one number over another, is called a

Mathematics
2 answers:
Andrei [34K]2 years ago
7 0
Fraction po

#carryonlearning
lbvjy [14]2 years ago
3 0

Answer:

its called a frcaction

Step-by-step explanation:

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A bank quotes an interest rate as 0.06341 annual effective yield. What interest rate, compounded monthly, will provide that
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Answer:

  0.06164

Step-by-step explanation:

The effective annual rate obtained by compounding nominal annual rate r monthly is ...

  eff rate = (1 +r/12)^12 -1

Then the value of r is ...

  r = 12×((eff rate) +1)^(1/12) -1)

For the given effective rate, that is ...

  r = 12×(1.06341^(1/12) -1) ≈ 0.06164 . . . . nominal annual interest rate

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Which matrix equation can be used to solve the system?<br> (2x+ 5y = 15<br> X + 3y = 18
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Find the values of x and y
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\large\boxed{y = 12, x = 3}

The two trapezoids are similar, so we can determine a common scale factor:

OL/UR = NM/TS

9/3 = 6/2

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Trapezoid ONML is 3x larger than UTSR, so:

RS = 4, LM = y

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g A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a specified number
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Complete Question

A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a specified number of times, and determines that 11 of the plates have blistered. Does this provide compelling evidence for concluding that more than 10% of plates blister under such circumstances?

A) State H_0 and H_a, (5 pts)

B) Test the hypothesis using the P-Value approach at a significance level of 4%: (15 pts)

Expert Answer

Answer:

a)H_0:p=0.10

  H_a:p>0.10

b) We fail to reject Null hypothesis

Step-by-step explanation:

From the question we are told that:

Sample size n=100

No. with blistered x=11

a)

Generally the Hypothesis given as

H_0:p=0.10

H_a:p>0.10

b)

Since p=0.10

Therefore

p'=\frac{11}{100}

p'=0.11

Test statistics

Z=\frac{p'-p}{\sqrt{p(1-p)}}

Z=\frac{0.11-0.10}{\sqrt{0.10*0.90/100}}

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From table

P-Value =0.092

Therefore

P-value >0.04 significance level

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