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3 years ago

A number between 0 and 1, expressed as one number over another, is called a

Mathematics

2 answers:

Andrei [34K]3 years ago

7 0

Fraction po

#carryonlearning

lbvjy [14]3 years ago

3 0

Answer:

its called a frcaction

Step-by-step explanation:

You might be interested in

Solve the following equation. Then place the correct mixed number in the box provided. 5x/7=22

natka813 [3]

We have that
<span> 5x/7=22
multiply by 7 both sides
5x=22*7-------> 5x=154
divide by 5 both sides
x=154/5
x=30.8--------> x=30 4/5

the answer is
x=30 4/5</span>

7 0

3 years ago

(05.03)

iren [92.7K]

x=2

1:Subtract 2x from both sides.

2:Combine 2/3 x and -2x to get -4/3

3:Subtract 3/8 from both sides. Anything subtracted from zero gives its negation.

4:Multiply both sides by -3/4,the reciprocal of -4/3

5:Multiply − 3/8 times − 4/ 3 by multiplying numerator times numerator and denominator times denominator.

6:Do the multiplications in the fraction −8(−3) over 3x4.

x=24/12

Divide 24 by 12 to get 2.

x=2

8 0

2 years ago

Giá trị x thoả mãn x(x − 3) + x − 3 =0 là

svet-max [94.6K]

Here we will use the trial and error method.

We will try putting different values of x.

$\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}$

<h2>Again,</h2><h3>x=3</h3>

$\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}$

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>

5 0

3 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

Read more about expressions at:

brainly.com/question/723406

#SPJ1

5 0

2 years ago

The amount of time that people spend at Grover Hot Springs Spa is normally distributed with a mean of 63 minutes and a standard

PtichkaEL [24]

Answer:

a) $X \sim N(63,18)$

Where $\mu=63$ and $\sigma=18$

b) $P(X>90)=P(\frac{X-\mu}{\sigma}>\frac{90-\mu}{\sigma})=P(Z>\frac{90-63}{18})=P(Z>1.5)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.5)=1-P(Z$

c) $P(X$

$P(Z$

d) $P(60$

$P(-0.167$

e) IQR = 75.13-50.87=24.26

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the amount of time that people spend at Grover Hot Springs of a population, and for this case we know the distribution for X is given by:

$X \sim N(63,18)$

Where $\mu=63$ and $\sigma=18$

Part b

We are interested on this probability

$P(X>90)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>90)=P(\frac{X-\mu}{\sigma}>\frac{90-\mu}{\sigma})=P(Z>\frac{90-63}{18})=P(Z>1.5)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>1.5)=1-P(Z$

Part c

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the normal standard table or excel:

$P(Z$

Part d

If we apply this formula to our probability we got this:

$P(60$

And we can find this probability with this difference:

$P(-0.167$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-0.167$

Part e

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.75$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

$P(X$