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lana [24]
2 years ago
15

Ma Lee swims for 4 weeks. Each week she swims for 6.3 hours. How many hours does Ma Lee swim in 4 weeks? *

Mathematics
2 answers:
boyakko [2]2 years ago
3 0

Answer:

13.2

Step-by-step explanation:

multiply 6.3×4

she swims 6.3 hours per week for 4 weeks. to find the answer you just need to multiply then together

Maurinko [17]2 years ago
3 0

Answer: Ma Lee swims for (4x6.3) which equals 25.2

Step-by-step explanation:

If you write them stacked on top of each other like this

6.3

6.3

6.3

6.3

when you add up the tenths place first you get 12 so regroup the 1 over to the ones place and put 2. Next add up 6's 6x4 equals 24 but dont forget the regrouped 1. Add 24+1=25. So altogether your answer is 25.2.

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A robot can complete 8 tasks in 5/6 hour. Each task takes the same amount of time.
ludmilkaskok [199]

Answer:

A. 6.25

B. Nine tasks

Step-by-step explanation:

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Micheal works 15.5 hours each week of a music store. He earns $9.48 per hour. How much does Micheal earn each week?
MissTica
All you have to do is times 15.5 with 9.48 and you get your answer witch is $146.94
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Solve for x: x²−9=5(x−3).
IceJOKER [234]

Answer:

Step-by-step explanation:

3 0
3 years ago
The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
2 years ago
The International Average Salary Income Database provides a comparison of average salaries for various professions. The data are
Tamiku [17]

Solution :

The monthly average salary and the standard deviation of the salaries of five different countries are provided. A person is interested in the relationship between the job performance, job satisfaction and the job compensation of the five different countries and try to compare them.

She calculated the z scores for accounting that makes $ ,500 per month as :

Country              z-score for salary $ 1,500

Brazil                       $\frac{1500-1351}{337.80} = 0.44$

US                          $\frac{1500-3370}{1011} = -1.85$

China                     $\frac{1500-165}{24.80} = 53.83$

Slovakia                 $\frac{1500-646}{96.80} = 8.82$

Kuwait                    $\frac{1500-2697}{808.20} = -1.48$

From above it is clear that an account from China getting  z score of 53.83 will ne more pleased than other countries because the salary of $1,500 in one month for this particular country corresponds to the highest z score.

7 0
3 years ago
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