Answer:
The 64 ounce jug of milk costs $0.010 more per ounce than the 128 ounce jug of milk/
Step-by-step explanation:
3.20/128=$0.025 per ounce jug of milk
2.24/64=$0.035 per ounce jug of milk
0.035 - 0.025 = .010
the answer for this is 84915
see the attached figure with the letters
1) find m(x) in the interval A,BA (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100
2) find m(x) in the interval B,CB(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20
3)
find n(x) in the interval A,BA (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x
4) find n(x) in the interval B,CB(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30
5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44
6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72
for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72
<span> h'(x) = 1.44 ------------ > not exist</span>
Answer:
The durations of movies in minutes can only take on integer values from 0 to 60. Therefore, it is a discrete data.
Answer:
Number of small candles = 12
Number of large candles = 16
Step-by-step explanation:
Total candles = 28
x + y = 28 ---------------(I)
Cost of 'x' small candles = 4 *x = 4x
Cost of 'y' large candles = 6 *y = 6y
Total amount = $144
4x + 6y = 144 -------------(II)
Multiply equation (I) by (-4) and then add the equation. So, x will be eliminated and we can find the value of 'y'
(I) * (-4) -4x - 4y = -112
(II) <u> 4x + 6y = 144</u> {Now, add}
2y = 32
y = 32/2
y = 16
Plug in y = 16 in equation (I)
x + 16 = 28
x = 28 - 16
x = 12