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jasenka [17]
3 years ago
6

Help me plz im tired and bored and dis the last thing me have to do

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0
6: I would pick D
1: D again
2: I would choose A

Hope this helps
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Find the midpoint of the segment with the given endpoints.<br><br><br> M(–2, 1) and N(–3, 2)
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3 years ago
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Perimeter of triangle:20
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3 years ago
Solve for J: 15(j-3)+3j&lt;45
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3 0
3 years ago
what does the slope of -1 tell you about thr relationship between lengths and widths of rectangles with perimeter 24?
NeX [460]

Using linear function concepts, the slope of -1 means that when one of the length/width is increased by 1, the other is decreased by 1.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0.

In this problem:

  • The lengths and the widths are interchangeable, that is, either can be considered as the input or as the output.
  • The slope of -1 means that when the input in increased by 1, the output is decreased by -1, that is, when one of the length/width is increased by 1, the other is decreased by 1.

You can learn more about linear function concepts at brainly.com/question/24808124

8 0
2 years ago
Now suppose that bigger cups are ordered and the machine’s mean amount dispensed is set at μ=12. Assuming we can precisely adjus
Elina [12.6K]

Answer:

σ should be adjusted at 0.5.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean 12.

Assuming we can precisely adjust σ, what should we set σtobe so that the actual amount dispensed is between 11 and 13 ounces, 95% of the time?

13 should be 2 standard deviations above the mean of 12, and 11 should be two standard deviations below the mean.

So 1 should be worth two standard deviations. Then

2\sigma = 1

\sigma = \frac{1}{2}

\sigma = 0.5

σ should be adjusted at 0.5.

4 0
2 years ago
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