Answer:
B. It was necessary that each of the two phage components, DNA and protein, be identifiable upon recovery at the end of the experiment.
Explanation:
Hershey and Martha Chase used radiolabeled the DNA of some of the bacteriophage cells with phosphorus (32P). They radiolabeled the sulfur (35S) of the coat protein in the second batch of the phage cells. They infected some of the bacterial cells with phage having radiolabeled DNA while the other <em>E. coli</em> cells were infected with the phage carrying radiolabeled coat protein. This allowed the clear identification of the radiolabelled molecule (DNA or protein) present in the host cell.
They observed that the <em>E. coli </em>cells infected with phage having radiolabeled DNA exhibited the radioactivity while the other batch of the host cell did not show it.
Your answer would be C.It encloses the cytoplasm.
Carbon Monoxide has 2 atoms total - one atom of carbon (C) and one atom of oxygen (O) chemical formula is CO
Ethylene has 6 atoms total, 2 atoms of carbon (C) and 4 atoms of hydrogen (H), chemical formula is C2H4.
Ethylene has four more atoms than carbon monoxide (6-2) = 4
Answer:
it preserved and resourcefully used
A codon is a tree letter nucleotide sequence in the mRNA. The tRNA anticodon attached to the corresponding amino acid recognizes the mRNA codon. A single amino acid can have more than one codon.
The serine codon can be one of the following:
<span>TCT, TCC, TCA, TCG, AGT, AGC</span>