The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
Learn more about polynomials at: brainly.com/question/2833285
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Answer:
C) ½
Step-by-step explanation:
P(C and D) = 150/300
= ½
The functions supplied appear to be the same? Regardless:
We have the equation y = 5x.
Therefore the gradient of this graph will be 5, so for every 1 increase in the y axis, there will be 5 in the x.
It will appear as a straight line passing through the origin and the point (1, 5).
Answer:
Option E
Step-by-step explanation:
The standard equation of circle is:- (x-h)² + (y-k)² = r²
where (h,k) is center point and r is radius
If radius r is decreased then also (h,k) remains same, only r² increases
Equation given in question is x² + y² + Cx + Dx + E=0
So, C and D will remain same but E will increase
Answer:
length: 23 m; width: 11 m.
Step-by-step explanation:
The perimeter of a rectangle is twice the sum of its length and width, so that sum is 34 m. Then you can write two equations in length and width:
l + w = 34
l - w = 12
Adding these together gives you ...
2l = 46
l = 23 . . . . . . divide by 2
Then the width is
w = 23 -12 = 11
The length and width are 23 m and 11 m, respectively.
