1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ASHA 777 [7]
2 years ago
14

Karen has 2 potatoes and she and she smashed one on your head how many does she have now

Mathematics
1 answer:
Tatiana [17]2 years ago
6 0
One potato...at least i think so
You might be interested in
Find the area of the figure
kherson [118]
Add the sides together and u get 19!
8 0
3 years ago
Rewrite 10(7g-9h)-4h-8(-h+8g)10(7g−9h)−4h−8(−h+8g) in simplest terms
aivan3 [116]
10(7g-9h)-4h-8(-h+8g)
solve for g
7g + 8g since both are positive
15g
solve for h
9h+4h since both are negative
-14h
10-8 since the 8 is negative
12
12(15g-14h)


Since you typed the same equation twice I didn’t know if you meant to , so if it was meant to be doubled it would be

4(30g-28h)
6 0
2 years ago
The average number of annual trips per family to amusement parks in the UnitedStates is Poisson distributed, with a mean of 0.6
IrinaK [193]

Answer:

a) 0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.

b) 0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.

c) 0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.

d) 0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.

e) 0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson distributed, with a mean of 0.6 trips per year

This means that \mu = 0.6n, in which n is the number of years.

a.The family did not make a trip to an amusement park last year.

This is P(X = 0) when n = 1, so \mu = 0.6.

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.6}*(0.6)^{0}}{(0)!} = 0.5488

0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.

b.The family took exactly one trip to an amusement park last year.

This is P(X = 1) when n = 1, so \mu = 0.6.

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 1) = \frac{e^{-0.6}*(0.6)^{1}}{(1)!} = 0.3293

0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.

c.The family took two or more trips to amusement parks last year.

Either the family took less than two trips, or it took two or more trips. So

P(X < 2) + P(X \geq 2) = 1

We want

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.5488 + 0.3293 = 0.8781

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.8781 = 0.1219

0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.

d.The family took three or fewer trips to amusement parks over a three-year period.

Three years, so \mu = 0.6(3) = 1.8.

This is

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-1.8}*(1.8)^{0}}{(0)!} = 0.1653

P(X = 1) = \frac{e^{-1.8}*(1.8)^{1}}{(1)!} = 0.2975

P(X = 2) = \frac{e^{-1.8}*(1.8)^{2}}{(2)!} = 0.2678

P(X = 3) = \frac{e^{-1.8}*(1.8)^{3}}{(3)!} = 0.1607

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1653 + 0.2975 + 0.2678 + 0.1607 = 0.8913

0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.

e.The family took exactly four trips to amusement parks during a six-year period.

Six years, so \mu = 0.6(6) = 3.6.

This is P(X = 4). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.1912

0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.

4 0
3 years ago
A box that has a width of 32 inches and a length of 60 inches is used to ship
Kisachek [45]
D.68

A squared plus b squared equals c squared and so add the two lengths given and square them which gives you the hypotenuse squared so then find the square root of your result which is 68
6 0
3 years ago
a sequence has a first term of 2 and a constant ratio of _3/2 what are the first five terms of the sequence
soldi70 [24.7K]
This is a geometric sequence with a=2, r= -3/2.
Therefore,
a₁ = 2
a₂ = 2*(-3/2) = -3
a₃ = 2*(-3/2)² = 9/2 = 4.5
a₄ = 2(-3/2)³ = -27/4 = -6.75
a₅ = 2(-3/2)⁴ = 81/8 = 10.125

Answer:
In fractions, the first five terms are
     2, -3, 9/2, -27/4, 81/8
In decimals, the first five terms are
     2.000, -3.000, 4.500, -6.750, 10.125


5 0
3 years ago
Other questions:
  • (6,2),(9,r),m=-1 find the value of r
    13·1 answer
  • Please help me solve 41 and 42
    12·1 answer
  • Their are 35 green marbles out of 60 marbles in the bag what is the ratio of the green marbles to total marbles?
    6·1 answer
  • When two lines are cut by a transversal, if the alternate interior angles are equal in measure, then the lines are parallel.
    11·2 answers
  • the half-life of colbalt-60 (used in radiation therapy) is 5.26 years (actual data). How much a of 200 g sample of colbalt-60 wi
    15·1 answer
  • What is 30mm x 3cm 3cm?
    11·1 answer
  • What is the answer? PLZ help me
    12·1 answer
  • Write your answer in simplest radical form​
    8·1 answer
  • Determine if the two triangles are congruent. If they are, state how you know.
    9·1 answer
  • A tangent to a circle passes through the center of the circle<br>True<br>false<br>sometimes true​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!