Answer: 10 and 11
Step-by-step explanation: The best way to think about it is to think of the squares of numbers that equal close to 104. 10 squared is 100, and 11 squared is 121. Since 104 is between these two, we can assume that the square root of 104 must be in between their square roots, 10 and 11.
Answer:
=5t+6
Step-by-step explanation:
because 5 has a variable which is t and 6 doesn't that is why we can't add it
Answer:
48
Step-by-step explanation:
Plug in 16 to the function:
f(16)=1/3(4-16)^2
=1/3(-12)^2
=144(1/3)
=48
Answer:
5/3
Step-by-step explanation:
1/2 x = 5/6
Multiply by 2 on each side
(1/2 * 2)x = (5/6)2
x = 5/3
Answer:
x = 4 ; y = 8
Step-by-step explanation:
we can use a system of two equation
x+1 = y-3
y-5 = 2x-5
we can find x in the first equation
x = y -4
we can now substitute x with this value in the second equation
y-5 = 2(y-4)-5
y = 2y-8
y = 8
we can now find x
x = 8-4 = 4
verify
2(4)-5 = 3
8-5 = 3
8-3 = 5
4 + 1 = 5