The answer is A.They push one another apart
Answer:They are equal and act in opposite directions.
Explanation:Newton's third law of motion states that for every action there is an equal and opposite reaction. In the case of Bode's rocket, the pressurized air in the bottle forces the water to gush downward out of the bottle, causing the rocket to launch upward into the air. The force of the water gushing downward is equal to the upward force on the rocket. So, the two forces are equal and act in opposite directions.
Answer:
The corridor's distance is "90 m".
Explanation:
- She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1.
- Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled.
- Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop.
- The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.
- Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.
Now,
⇒ 
⇒ 
The total distance of the corridor will be:
= 
= 
= 
= 
The frequency of the human ear canal is 2.92 kHz.
Explanation:
As the ear canal is like a tube with open at one end, the wavelength of sound passing through this tube will propagate 4 times its length of the tube. So wavelength of the sound wave will be equal to four times the length of the tube. Then the frequency can be easily determined by finding the ratio of velocity of sound to wavelength. As the velocity of sound is given as 339 m/s, then the wavelength of the sound wave propagating through the ear canal is
Wavelength=4*Length of the ear canal
As length of the ear canal is given as 2.9 cm, it should be converted into meter as follows:

Then the frequency is determined as
f=c/λ=339/0.116=2922 Hz=2.92 kHz.
So, the frequency of the human ear canal is 2.92 kHz.
Answer:
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Explanation:
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