Answer:
The answer is below
Explanation:
Because of the resistance of transmission lines, high current along the line leads to large voltage drop. This voltage drop causes low efficiency because the voltage at the receiving end is far less than that at the sending end.
Therefore there is need to transmit at a higher voltage (smaller current) than that required by distribution because of efficiency.
Hence, For safety and efficiency, the voltage must be large in the transmission lines and small in the distribution lines.
Answer:
C) A ratio based on the mass of a carbon-12 atom
Explanation:
For each element, there is a characteristic number of protons, this number represent a type of atom and its called the atomic number
On the other hand we have the number of neutrons, and for one element which difers only on the number of neutrons, we have different isotopes from one element.
Together, protons and neutrons define the mass number
One property linked with the mass number, is the atomic mass, which is formerly expressed as "uma" (atomic mass unit)
By definition, one atom of carbon-12 (with 6 neutrons) has an atomic mass of 12 umas
Since acceleration is constant, we can use the formula
v² - u² = 2a ∆x
where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then
0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x
⇒ ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m
Answer:
The correct option is;
How loud or soft the sound is
Explanation:
The loudness of a sound wave is given by the amount of energy that the pressure wave carries and it is measured in decibels (dB) which is the relative intensity of the pressure wave of a sound to the standard pressure
A loud sound has a high amplitude and a soft sound has a low amplitude, such that as the amplitude of the sound is increased, due to increased energy input, the sound becomes louder, and as the amplitude of the sound is decreased due to reduced energy input, the sound becomes softer.
Answer:
A) its internal (thermal) energy does not change.
Explanation:
When a fixed amount of ideal gas goes through an isothermal expansion
