Question

Each propeller of the twin-screw ship develops a full-speed thrust of F = 285 kN. In maneuvering the ship, one propeller is turning full speed ahead and the other full speed in reverse. What thrust P must each tug exert on the ship to counteract the effect of the ship's propellers?

Answer 1

Answer:

tug_tug = 570 10³ l

Explanation:

In this problem, each propeller creates a force that makes the boat rotate, so the tugs have to create a die of equal magnitude rep from the opposite direction

           ∑ τ = 0

           F1 la+ (-F1) (-l) = τ-tug

           τ-tug = 2 f1 l

            τ-tug = 2 28510³ l

            tug_tug = 570 10³ l

where the is the distance from the propane axis to the point where the ship turns

This force may be less depending on where the tug is.