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4vir4ik [10]
3 years ago
7

Sheldon also picks tomatoes from his garden. He picked 4 4/10 but 1.5 were rotten and had to be thrown away. How many kilograms

of tomatoes were not rotten? Write an equation that shows how you reached your answer.
Mathematics
1 answer:
velikii [3]3 years ago
8 0

Given:

Number of tomatoes Sheldon picks = 4\dfrac{4}{10} kg

Rotten tomatoes = 1.5 kg

To find:

How many kilograms of tomatoes were not rotten?

Solution:

Number of tomatoes Sheldon picks = 4\dfrac{4}{10} kg

                                                            = \dfrac{4(10)+4}{10} kg

                                                            = \dfrac{40+4}{10} kg

                                                            = \dfrac{44}{10} kg

                                                            = 4.4 kg

Rotten tomatoes = 1.5 kg

Remaining tomatoes which are not rotten is

Required tomatoes = Tomatoes Sheldon picks - Rotten tomatoes

                                = 4.4-1.5

                                = 2.9 kg

Therefore, the tomatoes which were not rotten is 2.9 kg.

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In ΔQRS, s = 2.3 inches, ∠S=51° and ∠Q=44°. Find the area of ΔQRS, to the nearest 10th of an square inch.
postnew [5]

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = 180^{o}

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<R = 180^{o} - 95

    = 85^{o}

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Applying the Sine rule, we have;

\frac{q}{SinQ} = \frac{r}{SinR} = \frac{s}{SinS}

Using \frac{r}{SinR} = \frac{s}{SinS}

\frac{r}{Sin 85} = \frac{2.3}{Sin51}

r = \frac{2.3*Sin85}{sin51}

  = 2.9483

r = 2.9 inches

Also, \frac{q}{SinQ} = \frac{s}{SinS}

\frac{q}{Sin44} = \frac{2.3}{Sin51}

q = \frac{2.3*Sin44}{Sin51}

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q = 2.0 inches

From Herons formula,

Area of a triangle = \sqrt{s(s-q)(s-r)(s-s)}

s = \frac{2.3 + 2.0 + 2.9}{2}

  = 3.6

Area of ΔQRS = \sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}

                        = 2.2895

Area of ΔQRS = 2.3 square inches

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The average (or mean) annual rainfall for Bramford, Ohio is 51 inches, and the rainfall for last year was 29 inches. What is the
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The change in rainfall between the rainfall last year and the average (or mean) annual rainfall is 22 inches

<h3>What is the change in rainfall between the rainfall last year and the average (or mean) annual rainfall?</h3>

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