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aniked [119]
4 years ago
12

In a​ triangle, the measure of the first angle is twicetwice the measure of the second angle. the measure of the third angle is

80 degrees80° more than the measure of the second angle. use the fact that the sum of the measures of the three angles of a triangle is 180degrees° to find the measure of each angle.
Mathematics
1 answer:
LiRa [457]4 years ago
7 0
A = first angle, b = 2nd angle, c = 3rd angle

a = 2b
c = b + 80
a + b + c = 180

2b + b + b + 80 = 180
4b + 80 = 180
4b = 180 - 80
4b = 100
b = 100/4
b = 25 <=== 2nd angle

a = 2b
a = 2(25)
a = 50 <=== 1st angle

c = b + 80
c = 25 + 80
c = 105 <=== 3rd angle
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Step-by-step explanation:

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Area of circle 3 outside circle 2    = A₃

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A₁  =  π*r₁²

According to problem statement  A₂  = π*r₂²  -   A₁

A₂  =  π*r₂²  -   π*r₁²      ⇒         A₂  =  π* (r₂²   - r₁²)

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A₁ /A₂  =  r₁² / (r₂²   - r₁²)

b)  A₂ /A₃        

A₂  =   π* (r₂²   - r₁²)

And

A₃   =  π* (r₃²   - r₂²)

Therefore

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A₂ /A₃  = (r₂²   - r₁²) / (r₃²   - r₂²)

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