<u>Answer:</u>
(a): The expression of equilibrium constant is ![K_{eq}=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
(b): The equation to solve the concentration of NO is ![[NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7BK_%7Beq%7D%5Ctimes%20%5BN_2%5D%5Ctimes%20%5BO_2%5D%7D)
(c): The concentration of NO is 0.0017 M.
<u>Explanation:</u>
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term 
(a):
The given chemical equation follows:
The expression for equilbrium constant will be:
(b):
The equation to solve the concentration of NO follows:
......(1)
(c):
Given values:
![[N_2]_{eq}=0.166M](https://tex.z-dn.net/?f=%5BN_2%5D_%7Beq%7D%3D0.166M)
![[O_2]_{eq}=0.145M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D0.145M)
Plugging values in equation 1, we get:
![[NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B%281.2%5Ctimes%2010%5E%7B-4%7D%29%5Ctimes%200.166%5Ctimes%200.145%7D)
![[NO]=\sqrt{2.88\times 10^{-6}}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B2.88%5Ctimes%2010%5E%7B-6%7D%7D)
![[NO]=0.0017 M](https://tex.z-dn.net/?f=%5BNO%5D%3D0.0017%20M)
Hence, the concentration of NO is 0.0017 M.
Answer:
1. The enthalpy change for the backward reaction is –20 KJmol¯¹
2. The forward reaction is endothermic.
3. The activation energy for the forward reaction is +70 KJmol¯¹.
Explanation:
Considering the diagram given above, the following data were obtained:
1. The enthalpy change for the forward reaction being is +20 KJmol¯¹ and so, the enthalpy change for the backward reaction is –20 KJmol¯¹
2. The heat energy of the product is higher than that of the reactant. Therefore, the forward reaction is endothermic.
3. Activation energy is the minimum energy needed to be overcome in order for the reaction to proceed to product. It can be obtained from the energy profile diagram by considering the energy between the reactants and the peak.
For the question given above, Activation energy = 20 + 50
Activation energy = +70 KJmol¯¹
Answer:C it’s gravitational potential
Explanation:I took the test
