Answer:
they all have different chemical compositions from earth
Venus is more filled with carbon dioxide and nitrogen
earth is filled more with oxygen and nitrogen
mars is filled more with carbon dioxide and carbon monoxide
so ur answer is C
it cant be B as scientists and NASA are still in the look out for life, D has nothing to do with chemicals and atmosphere, and its not A cuz they all dont have the same similiar chemical.
~batmans wife dun dun dun....
The mass of ethanol (alcohol) = 538.016 g
<h3>Further explanation</h3>
Given
Reaction
C₁₂H₂₂O₁₁(aq)+H₂O(I) = CH₃CH₂OH(aq)+CO₂(g)
1 kg of sugar = 1000 g
Required
The mass of ethanol
Solution
Balanced equation
C₁₂H₂₂O₁₁(aq)+H₂O(I) = 4CH₃CH₂OH(aq)+4CO₂(g)
mol of sugar (MW = 12.12+22.1+11.16=342 g/mol) :
mol = mass : MW
mol = 1000 g : 342 g/mol
mol = 2.924
From the equation, mol ratio of C₁₂H₂₂O₁₁ : CH₃CH₂OH = 1 : 4, so mol ethanol =
= 4 x mol sugar
= 4 x 2.924
= 11.696
Mass of ethanol(MW=46 g/mol) :
mass = mol x MW
mass = 11.696 x 46
mass = 538.016 g
Answer:
![[N_2]=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3D0.0866M)
Explanation:
Hello there!
In this case, in agreement to the chemical reaction, it is possible for us to figure out the equilibrium concentration of the N2 product, via an ICE table plugged in the equilibrium expression:
![Kc=\frac{[N_2][O_2]}{[NO]^2}\\\\2.4x10^3=\frac{x*x}{(0.175-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BN_2%5D%5BO_2%5D%7D%7B%5BNO%5D%5E2%7D%5C%5C%5C%5C2.4x10%5E3%3D%5Cfrac%7Bx%2Ax%7D%7B%280.175-2x%29%5E2%7D)
In such a way, when solving for x via quadratic equation or just a solver, it is possible to obtain:
In such a way, since the root 0.0884 M produce a negative concentration of NO (0.175-2*0.0884=-0.0018M), we infer that the correct root is 0.0866 M; therefore, the concentration of N2 at equilibrium is equal to x:
![[N_2]=x=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3Dx%3D0.0866M)
Best regards!
8.97 g/cm^
D=m/v
D=43.5/4.85cm^3
D=8.97 g/cm^3
Answer:
612 K
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 306 K
Initial pressure (P₁) = 150 kPa
Final pressure (P₂) = 300 kPa
Volume = 4 L = constant
Final temperature (T₂) =?
Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:
P₁ / T₁ = P₂ / T₂
150 / 306 = 300 / T₂
Cross multiply
150 × T₂ = 306 × 300
150 × T₂ = 91800
Divide both side by 150
T₂ = 91800 / 150
T₂ = 612 K
Thus, the new temperature of the gas is 612 K
