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lesya692 [45]
3 years ago
15

Pls answer this asap

Chemistry
1 answer:
horsena [70]3 years ago
5 0

Answer:

1. The enthalpy change for the backward reaction is –20 KJmol¯¹

2. The forward reaction is endothermic.

3. The activation energy for the forward reaction is +70 KJmol¯¹.

Explanation:

Considering the diagram given above, the following data were obtained:

1. The enthalpy change for the forward reaction being is +20 KJmol¯¹ and so, the enthalpy change for the backward reaction is –20 KJmol¯¹

2. The heat energy of the product is higher than that of the reactant. Therefore, the forward reaction is endothermic.

3. Activation energy is the minimum energy needed to be overcome in order for the reaction to proceed to product. It can be obtained from the energy profile diagram by considering the energy between the reactants and the peak.

For the question given above, Activation energy = 20 + 50

Activation energy = +70 KJmol¯¹

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Answer:

The total energy to break all the bonds in 1 mole of 1-propanol, C₃H₈O, is 4411 kJ/mol

Explanation:

We note that propanol, C₃H₈O is also known as 1-propanol is written as follows;

CH₃CH₂CH₂OH which gives

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Hence, the total number of bonds are;

C-H Bonds = 3 + 2 + 2 = 7

C-O Bonds = 1

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C-C Bonds = 2

The bond energies are as follows;

C-H Bonds = 413 kJ/mol

C-O Bonds = 358 kJ/mol

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Energy required to break the bonds in 1-propanol is therefore;

C-H Bonds = 413 kJ/mol × 7 = 2,891 kJ/mol

C-O Bonds = 358 kJ/mol × 1 = 358 kJ/mol

O-H Bond = 468 kJ/mol × 1 = 468 kJ/mol

C-C Bonds = 347 kJ/mol × 2 = 694 kJ/mol

The total energy to break all the bonds in 1 mole of 1-propanol = 4411 kJ/mol.

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