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H2so4+nai= i2+h2o+h2s+na2so4. The equivalent weight of h2so4 is

OleMash [197]

5H₂SO₄ + 8NaI = 4I₂ + 4H₂O + H₂S + 4Na₂SO₄

S⁺⁶ + 8e⁻ = S⁻² f=8
2I⁻ - 2e⁻ = I₂

M(H₂SO₄)=98 g/mol
M(eqi)=98/8=12.25 g/mol

4 0

3 years ago

Read 2 more answers

1.Complete the balanced neutralization equation for the reaction below:

Alexxx [7]

1. $H_{2}$ S $O_{4}$ + Sr(OH) $_{2}$ ⇒ SrSO4 + 2 H2O is the balanced reaction.

2. 0.034 liters of KI will be required completely react with 2.43 g of Cu(NO3)2.

3. 0.55 liters is the volume in L of a 0.724 M Nal solution contains0.405 mol of NaI.

4. 33.3 ml many mL of 0.300 M NaF would be required to make a 0.0400 M solution of NaF when diluted to 250.0 mL with water

Explanation:

Balance chemical reaction of neutralization:

1. $H_{2}$ S $O_{4}$ + Sr(OH) $_{2}$ ⇒ SrSO4 + 2 H2O

2. Data given:

balance chemical reaction:

2Cu(NO₃)₂(aq) + 4KI(aq) → 2CuI(aq) + I₂(s) + 4KNO₃(aq)

molarity of KI = 0.209 M

mass of Cu(NO₃)₂ = 2.43 grams

number of moles of Cu(NO₃)₂ will be calculated as:

number of moles = $\frac{mass}{atomic mass of 1 mole}$

atomic mass of Cu(NO₃)₂ = 187.56 grams/mole

putting the values in the equation,

number of moles= $\frac{2.43}{187.56}$

= 0.0129 moles

2 moles of Cu(NO₃)₂ will react with 4 moles of KI

0.0129 moles will react with x moles of KI

$\frac{4}{2}$ = $\frac{x}{0.0129}$

x = 0.0258

atomic mass of KI = 166.00 grams/mole

mass = 166.00 x 0.0258

= 4.28 grams or ml is the final volume of KI

so molarity = $\frac{number of moles}{volume in litres}$

so molarity of KI is 0.0258 M, volume is 1 litre.

Using the formula

Minitial x Vinitial = M final Vfinal

V initial = $\frac{M final Vfinal}{Minitial}$

= $\frac{4.28 X 0.209}{0.0258}$

= 34.67 ml 0.034 liters of KI will be required.

3) Data given:

molarity of NaI = 0.724

number of moles of NaI =?

Volume in litres =?

formula used:

molarity = $\frac{number of moles}{volume in liters}$

volume in litres = $\frac{0.405}{0.724}$

= 0.55 liters is the volume

4) Data given:

Initial molarity = 0.3 M

initial volume = ?

final molarity = 0.04 M

final volume diluted by = 250 ml

formula used:

M initial X Vinitial = Mfinal X V final

putting the values in the equation:

Vinitial = $\frac{0.04 X 250}{0.3}$

= 33.3 ml of 0.3 M solution will be required.

5 0

4 years ago

Temperature also affects the motion of atoms in a gas. Given what you know about temperature, pressure, and volume, which statem

vampirchik [111]

Answer:

C) As a gas is heated, the pressure decreases.

Explanation:

From the choices given, the statement that "as a gas is heated, the pressure decreases is false".

When gases are heated, their molecules expands and the volume of the gas increases. In a fixed container, the pressure of the gases will also increases.

Gases lack internal cohesion and very weak to no intermolecular forces binding them together.
When they are subjected to heat, they gain more energy(kinetic energy) which causes them to begin to spread out.
Thus, they take up even more space allowing volume to increase appreciably.

3 0

3 years ago

Na: 1s22sC2pP3s C= D= E=

KengaRu [80]

Answer

1s22s22p63s1

Explanation:

5 0

3 years ago

Interpretacao gerais das praticas sobre densidade de amostra solido e liquido

Savatey [412]

Answer:

O sólido tem densidade mais alta em comparação ao líquido.

Explicação:

A densidade da amostra sólida é maior do que a densidade do líquido porque há pouco espaço entre as partículas do sólido. A densidade tem relação inversa com o volume de uma substância, se uma substância ocupa mais espaço então sua densidade é menor, enquanto se a substância ocupa menos espaço então tem maior densidade. As substâncias sólidas ocupam menos espaço em comparação com as substâncias líquidas, então podemos dizer que a densidade do sólido é maior do que as substâncias líquidas.

6 0

3 years ago