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dusya [7]
3 years ago
8

7th Grade

Mathematics
1 answer:
Furkat [3]3 years ago
7 0
The answer was is : The foot ball player is at school for 12 hours, I got this answer by multiplying 3 hours by 4 since 3 hours is a quarter and 4 quarters make up 100%.
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Cody bought two burgers and two
8_murik_8 [283]

Answer:

$5

Step-by-step explanation:

Let the cost of one burger be $b while the cost of one small fries be s

2 burgers and 2 small fries cost $14

This means that;

2b + 2s = 14

divide both sides by 2

b + s = 7 •••••••• (i)

Three burgers and four small fries cost $23

Mathematically;

3b + 4s = 23 •••••••• (ii)

From i , we can see that s = 7- b

we can now substitute this into equation ii

3b + 4(7-b) = 23

3b + 28 -4b = 23

4b -3b = 28 -23

b = $5

one burger costs $5

7 0
4 years ago
Which is true about x, the quotient of the division problem shown below? х 81 918 O The quotient contains a repeating decimal. O
Sergio [31]

Answer:

The answer is choice 2 and 3, that is "The quotient has a final decimal and the whole number is less than 11".

Step-by-step explanation:

The product of a ratio: amount (r) over other(s) (variance from 0) becomes mandatory to note this quotient and in the following case Thus q is = 0.0882352941.

\to \frac{81}{918}= 0.0882352941

It wasn't a repeating decimal, however a final decimal, so it's got an end.

Its quotient may be less than 11 in total.

Numbers of W = {0,1,2, ...} and 0 < 11 are provided for this entire series of data therefore It's real .

8 0
3 years ago
Tom used twenty gallons of water to
oksano4ka [1.4K]

Answer:

y=20x + 40x

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Enter the value of p so the expression 5/6-1/3nis equivalent to p(5-2n).
SIZIF [17.4K]
Take LCD of 6 and 3 = 6 is the lcm
5/6 -2/6n 
(5-2n)/6.

Now, what number can be multiplied to the right side of the equal sign to get the value of P

The answer is 1/6 as the left side is divided by 6, so multiply the right side by 1/6 to make it equivalent.
6 0
4 years ago
Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D
Nostrana [21]

Answer:

\displaystyle   \begin{cases} \displaystyle  {x} _{1} =  - p \\   \displaystyle x _{2}   =  -  q \end{cases}

Step-by-step explanation:

we would like to solve the following equation for x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}  +  \frac{1}{x}  =  \frac{1}{p  + q + x}

to do so isolate \frac{1}{x} to right hand side and change its sign which yields:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{1}{p  + q + x}  -  \frac{1}{x}

simplify Substraction:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{x - (q + p +  x)}{x(p  + q + x)}

get rid of only x:

\displaystyle  \frac{1}{p}  +  \frac{1}{q}    =  \frac{  - (q + p )}{x(p  + q + x)}

simplify addition of the left hand side:

\displaystyle  \frac{q + p}{pq}     =  \frac{  - (q + p )}{x(p  + q + x)}

divide both sides by q+p Which yields:

\displaystyle  \frac{1}{pq}     =  \frac{  -1}{x(p  + q + x)}

cross multiplication:

\displaystyle    x(p  + q + x)  =   - pq

distribute:

\displaystyle    xp  + xq +  {x}^{2} =   - pq

isolate -pq to the left hand side and change its sign:

\displaystyle    xp  + xq +  {x}^{2} + pq =  0

rearrange it to standard form:

\displaystyle   {x}^{2} +    xp  + xq  + pq =  0

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

\displaystyle  x( {x}^{} +   p ) + xq  + pq =  0

factor out q:

\displaystyle  x( {x}^{} +   p ) +q (x + p)=  0

group:

\displaystyle  ( {x}^{} +   p ) (x + q)=  0

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

\displaystyle   \begin{cases} \displaystyle  {x}^{} +   p  = 0 \\   \displaystyle x + q=  0 \end{cases}

cancel out p from the first equation and q from the second equation which yields:

\displaystyle   \begin{cases} \displaystyle  {x}^{}   =  - p \\   \displaystyle x  =  -  q \end{cases}

and we are done!

3 0
3 years ago
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