4x+1=1/3x+10
4x=1/3x+10-1
4x=1/3x+9
4x-3x=9
x=9
For that problem, all you have to do is add all of the trees up together. :3
Answer:
s = √(3V/[8 in])
Step-by-step explanation:
Where are "the following functions" that were mentioned in this problem statement? Please share them. Thanks.
The volume of a right square pyramid is V = (1/3)(area of base)(height). In more depth, V = (1/3)(s²)(h). We want to solve this for s.
Multiplying both sides by 3 to eliminate the fractional coefficient, we get:
3V = s²(h), and so s² = 3V/h.
Taking the square root of this, we get:
s = √(3V/h).
Now let's substitute the given numerical value for the height:
s = √(3V/[8 in]). We could also label this as a(V) as is done in the problem statement.
Answer:
21, 18, 15
Step-by-step explanation:
First term = a1
Second term = a2
Third term = a3
a1 = 21
a2
= a + d
= 21 - 3
= 18
a3
= a + 2d
= 21 + 2 ( - 3 )
= 21 - 6
= 15
The first 3 terms are 21, 18, 15.
The scale factor is 0.25, not 4 in this case. You can determine this by looking at the comparison of the triangles. The first triangle is 4.4 and the second one is 1.1, so the scale factor is determined by looking at what is happening to the first one to result in the second.
0.25 is 1/4. The second hypotenuse is 1/4 the hypotenuse of the first one.
