The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Real number, rational number
Given:
The equation is

To find:
The coefficient and reciprocal.
Solution:
We have,

Here,
is multiplied with x.
So, the coefficient of x is
.
To find the reciprocal, we need to interchange numerator and denominator of a fraction.
So, the reciprocal of
is 
Therefore, the reciprocal is 3.
Replace the x with 9, and the y with 1.
(x · y²)/-5 becomes (9 · 1²)/-5
1² is just 1, so you're doing 9 × 1 (which is = 9) over -5.
Therefore, your final answer is -9/5.
Answer:
21/10 or 2.1
Step-by-step explanation: