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matrenka [14]
3 years ago
15

What other information is needed to prove that Triangle CEB is congruent to Triangle AED by SAS congruence theorem?

Mathematics
1 answer:
Westkost [7]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Im pretty sure, but double check

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Find all the roots of the given function. Use preliminary analysis and graphing to find good initial approximations.
Evgesh-ka [11]

Answer:

  • x ≈ -0.107760269824
  • x ≈ 1.98779489573

Step-by-step explanation:

The quadratic portion of f(x) factors as (-4x)(x -2), so has zeros at x=0 and x=2. The cosine portion of f(x) will have a value of 1 at x=0 and a value of about -0.15 at x=2. Thus, we might expect roots to be slightly negative and near x=2. (It turns out that a not-unreasonable approximation of the cosine function as cos(x) ≈ 1-x²/2 can be usefully used to get better approximations of the roots in each case.)

A graphing calculator makes it easy to find initial approximations of the two roots. The graph shows them to be -0.108 and 1.988.

__

Many graphing calculators also include the ability to determine a numerical value of the derivative of a function. This makes it possible to write an iteration function after the fashion of Newton's Method iteration:

  g(x) = x -f(x)/f'(x)

where g(x) gives a new value for old guess x, and f'(x) is the derivative of f(x).

The calculator we used is interactive, so the value of g(x) is found even as you type the argument value x. That makes it possible to achieve full calculator accuracy for the root estimate simply by copying the approximate value into the expression g(x).

  x ∈ {−0.107760269824, 1.98779489573}

7 0
4 years ago
H(x) = -x^3-2x^2-3x+4; x=2
ioda

Answer:

h(2)=-18

Step-by-step explanation:

h(x)=-x^3-2x^2-3x+4\\Substituting\ x=2,\\h(2)=-(2)^3-2(2)^2-3(2)+4\\h(2)=-(8)-2*4-6+4\\h(2)=-8-8-6+4\\h(2)=-22+4\\h(2)=-18

4 0
3 years ago
9234/52<br> Give the answer and remainder
amm1812

Answer:

177 remainder 30

Step-by-step explanation:

Hope this helps! Pls give brainliest!

8 0
3 years ago
Read 2 more answers
A company issues 7% bonds with a par value of $200,000 at par on January 1. The market rate on the date of issuance was 6%. The
Step2247 [10]

Answer:

The cash  paid to the bondholder on July 1 is    Z =  $7000

Step-by-step explanation:

From the question we are told that

  The percentage bond issued by the company is n = 7%

    The par value of the bond is V =$200,000

     The market rate is r = 6%

So we are told that the bonds pay interest semiannually on January 1 and July

So the cash  paid to the bondholder on July 1 is mathematically evaluated as

Z =  V * \frac{7}{100} * \frac{1}{2}        

substituting value

   Z =  200000 * \frac{7}{100} * \frac{1}{2}  

      Z =  $7000

3 0
4 years ago
234 students in 9 different classrooms. What is the ratio of students to classrooms?
Vilka [71]

Answer:

26 students per classroom

Step-by-step explanation:

To solve this, the ratio 234 students:9 classrooms must be converted to:

s students:1 classroom

To convert the ratio, 9 was divided by 9 to get 1, and so you must also divide 234 by 9 to maintain the same ratio, which gives us the answer:

26 students: 1 classroom

5 0
3 years ago
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