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Marina CMI [18]

3 years ago

6

The graph of which function has a y-intercept of 3? On a coordinate plane, a parabola opens up. It goes through (negative 3, 3),

has a vertex at (negative 1.5, 0.75), and goes through (0, 3). On a coordinate plane, a parabola opens up. It goes through (1, 4), has a vertex at (3, 0), and goes through (5, 4). On a coordinate plane, a parabola opens up. It goes through (negative 5, 4), has a vertex at (negative 3, 0), and goes through (negative 1, 4). On a coordinate plane, a parabola opens up. It goes through (negative 4, 5), has a vertex at (negative 1, negative 4), and goes through (2, 5).

1 answer:

mixer [17]3 years ago

4 0

Answer:

It is A

Step-by-step explanation:

The guy below is wrong because I got a 100 on the quiz on Edge.

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Somolia's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 senior citizen ticke

timofeeve [1]

The price for senior citizens was 4 dollars and the price for the child tickets would be 7 dollars.

5 0

3 years ago

Let g(x) be the reflection of f(x) = 3x + 2 in the x-axis. What is a function rule for g(x)?

BartSMP [9]

The reflection of $f(x) = 3\cdot x + 2$ in the x-axis is $g(x) = -3\cdot x - 2$ . The function used to derive $g(x)$ is: $g(x) = -f(x)$ . (Correct choice: $g(x) = -3\cdot x - 2$ )

Mathematically speaking, a reflection in the x-axis is defined by the following expression:

$g(x) = -f(x)$ (1)

Where:

$f(x)$ - Original function.
$g(x)$ - Reflected function.

If we know that $f(x) = 3\cdot x + 2$ , then the expression for $g(x)$ is:

$g(x) = - (3\cdot x + 2)$

$g(x) = -3\cdot x - 2$

The reflection of $f(x) = 3\cdot x + 2$ in the x-axis is $g(x) = -3\cdot x - 2$ . The function used to derive $g(x)$ is: $g(x) = -f(x)$ .

We kindly invite to see this question on reflections: brainly.com/question/23558898

7 0

3 years ago

A committee at the College Board has been asked to study the SAT math scores for students in Pennsylvania and Ohio. A sample of

ozzi

Answer:

Step-by-step explanation:

From the given information:

The null hypothesis and the alternative hypothesis can be computed as:

$H_0 :\mu_1 -\mu_2 = 0$ (i.e. there is no difference between the SAT score for students in both locations)

$H_1 :\mu_1 -\mu_2 \geq0$ (i.e. there is a difference between the SAT score for students in both locations)

The test statistics using the students' t-test for the two-samples; we have:

$t = \dfrac{\overline x_1 -\overline x_2}{\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2} } }$

$t = \dfrac{580 -530}{\sqrt{\dfrac{105^2}{45}+\dfrac{114^2}{38} } }$

$t = \dfrac{50}{\sqrt{\dfrac{11025}{45}+\dfrac{12996}{38} } }$

$t = \dfrac{50}{\sqrt{245+342 } }$

$t = \dfrac{50}{\sqrt{587} }$

$t = \dfrac{50}{24.228}$

t = 2.06

degree of freedom = ( $n_1 + n_2$ ) -2

degree of freedom = (45+38) -2

degree of freedom = 81

Using the level of significance of 0.05

Since the test is two-tailed at the degree of freedom 81 and t = 2.06

The p-value = 0.0426

Decision rule: To reject $H_o$ if the p-value is less than the significance level

Conclusion: We reject the $H_o$ , thus, there is no sufficient evidence to conclude that there is a significant difference between the SAT math score for students in Pennsylvania and Ohio.

5 0

3 years ago

Somebody help me on this real quic plz

katrin [286]

Basically you are just multiplying 2 with the x-values. So...
x y
0 = 0
1 = 2
2 = 4
3 = 6
5 = 10
I hope this helps love! :)

5 0

3 years ago

A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. Following are the amounts measured in a

dlinn [17]

Answer:

The mean volume is 12 ounces.

Step-by-step explanation:

In this case we need to test whether the mean volume the machine fills the beverage cans with is 12 ounces or not.

The hypothesis for this test can be defined as:

<em>H₀</em>: The mean volume is 12 ounces. i.e. <em>μ</em> = 12 ounces.

<em>Hₐ</em>: The mean volume is not 12 ounces. i.e. <em>μ</em> ≠ 12 ounces.

As the population standard deviation is not known, we will use a <em>t</em>-test for single mean.

The sample mean and sample standard deviation is:

$\bar x=\frac{1}{n}\sum X\\=\frac{1}{8}\times [11.98+12.08+11.87+11.95+11.89+12.01+11.97+12.10]\\=11.98$

$\text{s} = \sqrt{\dfrac{\sum_{i=1}^{n}(x_i - \overline{x})^{2}}{n - 1}}\\=\sqrt{\dfrac{\sum_{i=1}^{n}(11.98 - 11.98)^{2}}{8 - 1}}+\sqrt{\dfrac{\sum_{i=1}^{n}(12.08- 11.98)^{2}}{8 - 1}}+...+\sqrt{\dfrac{\sum_{i=1}^{n}(12.10- 11.98)^{2}}{8 - 1}}\\=0.0815$ Compute the test statistic as follows:

$t=\frac{\bar x-\mu}{\s/\sqrt{n}}=\frac{11.98-12}{0.0815/\sqrt{8}}=-0.69$

The test statistic value is -0.69.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level, then the null hypothesis will be rejected.

Compute the <em>p</em>-value of the test as follows:

$p-value=2P(t_{7}$

*Use a <em>t</em>-table.

The significance level of the test is, <em>α</em> = 0.05.

<em>p</em>-value = 0.512 > <em>α</em> = 0.05

The null hypothesis was failed to be rejected.

Hence, it can be concluded that the mean volume is 12 ounces.

5 0

3 years ago