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Marina CMI [18]
2 years ago
6

The graph of which function has a y-intercept of 3? On a coordinate plane, a parabola opens up. It goes through (negative 3, 3),

has a vertex at (negative 1.5, 0.75), and goes through (0, 3). On a coordinate plane, a parabola opens up. It goes through (1, 4), has a vertex at (3, 0), and goes through (5, 4). On a coordinate plane, a parabola opens up. It goes through (negative 5, 4), has a vertex at (negative 3, 0), and goes through (negative 1, 4). On a coordinate plane, a parabola opens up. It goes through (negative 4, 5), has a vertex at (negative 1, negative 4), and goes through (2, 5).
Mathematics
1 answer:
mixer [17]2 years ago
4 0

Answer:

It is A

Step-by-step explanation:

The guy below is wrong because I got a 100 on the quiz on Edge.

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Nicholas is currently in eighth grade and intends to attend a state college when he finishes high school. Nicholas’s parents cur
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Answer:

20,814.00

これがお役に立てば幸いです。また、良い一日をお過ごしください

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-8=-(x+4). Please help I don't know the answer or steps to solve this equation.
Ne4ueva [31]

Answer:

x = 4

Step-by-step explanation:

First u need to distribute the -1 to (x + 4), creating the equation, -8 = -x - 4. Then add the -4 to both sides, and you get, -4 = -x. Then divide by -1 to both sides, and x = 4.

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3 years ago
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The length of a rectangle is 4 meters less than twice the width. If the area of the rectangle is 286 square​ meters, find the di
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Step-by-step explanation:

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2 years ago
There is a 70% chance that your car will get stuck in the snow during the next big snowfall. Given that you are already stuck in
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Given:
Probability that your car will get stuck in the snow: 70%
Probability that you will require a tow truck when stuck in the snow is 90%.

Probability that you're stuck in the snow and need a tow truck.

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6 0
2 years ago
Solve in attachment....​
olga2289 [7]

Answer:

A)2

Step-by-step explanation:

we would like to integrate the following definite Integral:

\displaystyle  \int_{0} ^{1} 5x \sqrt{x} dx

use constant integration rule which yields:

\displaystyle  5\int_{0} ^{1} x \sqrt{x} dx

notice that we can rewrite √x using Law of exponent therefore we obtain:

\displaystyle  5\int_{0} ^{1} x \cdot  {x}^{1/2} dx

once again use law of exponent which yields:

\displaystyle  5\int_{0} ^{1}  {x}^{ \frac{3}{2} } dx

use exponent integration rule which yields;

\displaystyle  5 \left( \frac{{x}^{ \frac{3}{2}  + 1  } }{ \frac{3}{2}  + 1} \right)  \bigg|  _{0} ^{1}

simplify which yields:

\displaystyle  2 {x}^{2}  \sqrt{x}   \bigg|  _{0} ^{1}

recall fundamental theorem:

\displaystyle  2 (  {1}^{2}) (\sqrt{1}  ) - 2( {0}^{2} )( \sqrt{0)}

simplify:

\displaystyle  2

hence

our answer is A

8 0
2 years ago
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