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3 years ago

A TV is listed for 35% off. If the original price was $550, what is the sale price?

Mathematics

2 answers:

almond37 [142]3 years ago

7 0

Answer:

357.50$

Step-by-step explanation:

550 x 35% =192.50$

550 - 192.50 = 357.50$

docker41 [41]3 years ago

3 0

How to calculate percent off?
Divide the number by 100 (move the decimal place two places to the left).
Multiply this new number by the percentage you want to take off.
Subtract the number from step 2 from the original number. This is your percent off number.

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2 stacked cubed. One cube has side lengths of 24 inches, and the second cube has side lengths of 12 inches. What is the total vo

Maurinko [17]

Answer:

15552 in^3

Step-by-step explanation:

Volume formula for a cube of side length s: V = s^3.

Then the total volume here is:

(24 in)^3 + (12 in)^3 = 15552 in^3

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3 years ago

Each part of a race is 1/10 mile marker finished 5 parts of the race how far did Marshall race

exis [7]

A half mile bc 1/10•5 = 5/10& thats 1/2

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3 years ago

Read 2 more answers

3. There are four teams in the raquetball league on the island of Allendine. In a season, they play each other once. Three point

andrew-mc [135]

Answer and Step-by-step explanation:

Team: Points. Results fetching points

Arcadia. 3+1. 1 win & 1 draw

Brextone. 3+1. 1 win & 1 draw

Cremore 1+1. 2 draws

Dunross. 3+3. 2 wins

a) Based on the previous data, we can conclude that the number of matches drawn was 4

b) Dunross defeated cremore since cremore did not win any league game and dunross reported no ties

c) Yes, you can get a prediction of the matches with their respective results as follows

Brextone drew with Cremore

Dunross beat Arcadia

Arcadia beat Brextone

Arcadia drew with Cremore

Dunross beat Cremore

7 0

3 years ago

Read 2 more answers

Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

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3 years ago

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