Answer:
1.40 moles.
Explanation:
The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -
In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.
Since, 2 moles of 
is formed by 4 moles of 
So, for 1.8 moles of amount of required moles of = 
In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.
Since, 2 moles of is formed by 5 moles of oxygen
So, for 1.40 moles of moles of 
required = 
Thus as of now we have 3.60 moles of and 3.50 moles of .
As in the reaction of formation of , oxygen is the limiting reagent.
So the moles of formed by the 3.50 moles of oxygen will be
= 
= 1.40 moles.
Answer:
Sulfur
Explanation:
<u>Valence electrons</u> are the group numbers. The group numbers are the numbers that go from left to right on the top. But since you can't have more than 8 valence electrons, the group numbers of 13-18, the valence electrons will actually be from 3-8. So 6 valence electrons would be group 16. That narrows it down a lot. The only elements in this group are oxygen, sulfur, selenium, tellurium, polonium, and livermorium.
Energy level are the period numbers. The period numbers are the numbers that go from top to bottom. So the 3rd energy level is the 3rd period. So when you look at the periodic table, under the 16 group and 3rd period, lies Sulfur.
Was there suppose to be a picture included?
Given:
Concentration 1 = 100.0 ml Concentration 2 = ?
Volume 1 = 0.100 M KCL Volume 2= 0.500 M KCL
Find Concentration 2
To get the concentration 2, follow this formula
C1V1 = C2V2
Solution
(100.0 ml) (0.100 m kcl) = (X ml) (0.500 m kcl)
transfer the volume 2 to the left side
(100.0 ml) (0.100 m kcl) = X ml
---------------------------------
0.500 m kcl
10.00ml / m kcl = Xml
-------------------- cancel the m kcl to let the ml be the remaining variable
0.500 m kcl
20.0 ml = x ml
So you will need 20.0 ml of 0.500 m kcl to made the solution of 100.0 ml of 0.100 m kcl
