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valina [46]
3 years ago
15

Fe2O3 + H2 --> Fe + H2O

Chemistry
1 answer:
sveticcg [70]3 years ago
4 0
A) 10.0g of Iron is \frac{10.0}{55.8}=179mmol of Iron.

One mole of dihydrogen is required to form one mole of iron, hence you'll need 0.179*1.00=0.179g of dihydrogen.

B) Likewise : 2.50g of Iron is \frac{2.50}{55.8}=44.8mmol of Iron, hence we'll need 44.8*(3*16+2*55.8)=7.15g of Fe2O3.
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So, theoretical yield of H_{2} = (0.550\times 2.016)g=1.11g

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