Molar mass Li2O = 7.0 x 2 + 16 => 30 g/mol
1 mole Li2O ---------- 30 g
( moles Li2O ) -------- 45.0 g
moles Li2O = 45.0 x 1 / 30
moles Li2O = 45.0 / 30
= 1.50 moles of Li2O
hope this helps!
Answer:
In 33.7 grams SnF2 we have 8.17 grams of F
Explanation:
Step 1: Data given
Mass of SnF2 = 33.7 grams
Molar mass of SnF2 = 156.69 g/mol
Molar mass of F = 19.00 g/mol
Step 2: Calculate moles of SnF2
Moles SnF2 = mass / molar mass
Moles SnF2 = 33.7 grams / 156.69 g/mol
Moles SnF2 = 0.215 moles
Step 3: Calculate moles F
For 1 mol SnF2 we have 2 moles F
For 0.215 moles SnF2 we have 2*0.215 = 0.430 moles F
Step 4: Calculate mass F
Mass F = moles F * molar mass F
Mass F = 0.430 moles * 19.00 g/mol
Mass F = 8.17 grams
In 33.7 grams SnF2 we have 8.17 grams of F
Answer:
D.) 2,000 kilocalories would be the correct answer.
Explanation:
Answer:
a) 26.98
b) 3
c) 3* 1.01 = 3.03
d) 3 *16 = 48
e) 26.98 + 3.03 + 48 = 78.01
f) 6.023 * 10²³
It will result in an increase in the rate of rxn
