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3 years ago

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How are prisms and pyramids alike and how are they different?

2 answers:

Nezavi [6.7K]3 years ago

5 0

sample

Prisms and pyramids are geometric shapes that have flat sides, flat bases and angles. So those are some similarities. However, the bases and side faces on prisms and pyramids differ. Prisms have two bases while pyramids only have one. There are a variety of pyramids and prisms, so not all shapes in each category look the same.

s344n2d4d5 [400]3 years ago

3 0

Prisms and pyramids are geometric shapes that have flat sides, flat bases and angles. So those are some similarities. However, the bases and side faces on prisms and pyramids differ. Prisms have two bases while pyramids only have one. There are a variety of pyramids and prisms, so not all shapes in each category look the same.

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Casey wants to buy a gym membership. Gym A has a $150 joining fee and costs $35 per month. Gym B has no joining fee and costs $6

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Answer:

Step-by-step explanation:

Gym A has a $150 joining fee and costs $35 per month.

Assuming that Casey wants to attend for x months, the cost of using gym A will be

150 + 35 times x months. It becomes

150 + 35x

Gym B has no joining fee and costs $60 per month.

Again, assuming that Casey wants to attend for x months, the cost of using gym B will be

60 × x months = 60x

A) To determine the number of months that it will both gym memberships to be the same, we will equate them.

150 + 35x = 60x

60x - 35x = 150

25x = 150

x = 150/25 = 6

It will take 6 months for both gym memberships to be the same.

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Plan B will cost 60 × 5 = $300

Plan B will be cheaper

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Please help with the question in the picture!

Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

<u>METHOD - I</u>

<u><em>Sin² C + Cos² C = 1</em></u>

Cos² C = 1 - Sin² C

Cos² C = $1 - \frac{9}{25}$

Cos² C = $\frac{25 - 9}{25}$

Cos² C = $\frac{16}{25}$

Cos C = $\sqrt{\frac{16}{25} }$

Cos C = $\frac{4}{5}$

As we know that

Tan C = $\frac{Sin C}{Cos C }$

<em>Tan C = $\frac{\frac{3}{5} }{\frac{4}{5} }$ </em>

<em>Tan C = $\frac{3}{4}$ </em>

<u>METHOD - II</u>

Given Sin C = $\frac{3}{5} = \frac{Height}{Hypotenuse}$

therefore,

AB ( Height ) = 3; BC ( Hypotenuse) = 5

<em>∵ ΔABC is Right triangle.</em>

<em>∴ By Pythagorean Theorem-</em>

<em>AB² + AC² = BC²</em>

<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>

<em>AC² = 5² - 3²</em>

<em>AC² = 25 - 9</em>

<em>AC² = 16</em>

<em>AC ( Base) = 4</em>

<em>Since, </em>

<em>Tan C = $\frac{Height}{Base}$ </em>

<em>Tan C = $\frac{AB}{AC}$ </em>

<em>Hence Tan C = $\frac{3}{4}$ </em>

<em />

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3 years ago

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4b.

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Answer:

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3 years ago