2t + 8 ≥ -4(t+1)
PEMDAS
2t + 8 ≥ -4t - 4
2t + 12 ≥ -4t
12 ≥ -6t
-2 ≤ t
To find the area of the shaded region you need find the area
of the shaded region and subtract the area of the unshaded region.
Area of a rectangle = width x length
A = (x + 10) x (2x + 5)
Next apply FOIL or
First Outer Inner Last
A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)
A= 2x2 + 5x + 20x + 50
A= 2x2 +25x +50
Area of a square= sides2
A= (x + 1)2
A= (x+1) (x+1)
Next apply FOIL or
First Outer Inner Last
A = (x *x) (1*x) (1*x) (1*1)
A = x2 + 1x + 1x +1
A= x2 + 2x +1
A= 2x2 +25x +50 - 2x2 +25x +50
A= 50x + 100
rhoumbus that is what I use and got right!!
Step-by-step explanation:
Answer:
π^2, 9.8 repeating, square root of 99.
Step-by-step explanation:
Answer:
I think its A........ I don't really know.
Step-by-step explanation:
5 x 2 = 10
3.14 x 10 = 31.4
